PLEASE HELP 50 pts + brainliest. 3. A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.
55). The light first enters the water at an angle of 25.0 degrees (from air to water). Draw a diagram. Use Snell’s Law to find the angle of refraction in the water and then in the glass. I don't know how to do this.
1 answer:
Answer: the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately
Explanation:
A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.55).
If the light first enters the water at an angle of 25.0 degrees (from air to water). That means
The incident angle = 25 degrees
Using Snell' law
n(air)/n(water) = sin 25/sin R
Where R is the angle of refraction
1/1.33 = sin 25/sin R
Make sin R the subject of formula
Sin R = sin 25 / 0.7518
Sin R = 0.5620
R = sin^-1(0.5620)
R = 34.2 degrees
This angle will be an incident angle when the light is travelling from the water to glass. Using Snell law agains,
1.33/1.55 = sin 34.2/sin R
Cross multiply
1.33 sin R = 0.87122
Make R the subject of formula
Sin R = 0.87122/1.33
Sin R = 0.6550
R = sin^-1(0.6550)
R = 40.9 degrees
Therefore, the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately.
Find the attached file for the figure
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y = d sin 16
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