Question

PLEASE HELP 50 pts + brainliest. 3. A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.55). The light first enters the water at an angle of 25.0 degrees (from air to water). Draw a diagram. Use Snell’s Law to find the angle of refraction in the water and then in the glass. I don't know how to do this.

Answer 1

Answer: the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately

Explanation:

A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.55).

If the light first enters the water at an angle of 25.0 degrees (from air to water). That means

The incident angle  = 25 degrees

Using Snell' law

n(air)/n(water) = sin 25/sin R

Where R is the angle of refraction

1/1.33 = sin 25/sin R

Make sin R the subject of formula

Sin R = sin 25 / 0.7518

Sin R = 0.5620

R = sin^-1(0.5620)

R = 34.2 degrees

This angle will be an incident angle when the light is travelling from the water to glass. Using Snell law agains,

1.33/1.55 = sin 34.2/sin R

Cross multiply

1.33 sin R = 0.87122

Make R the subject of formula

Sin R = 0.87122/1.33

Sin R = 0.6550

R = sin^-1(0.6550)

R = 40.9 degrees

Therefore, the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately.

Find the attached file for the figure