Answer:
23.67 m
Explanation:
We are given;
Frequency; f = 0.3 Hz
Speed; v = 7.1 m/s
Now, formula to get the wavelength is from the wave equation which is;
v = fλ
Where λ is wavelength
Making λ the subject, we have;
λ = v/f
λ = 7.1/0.3
λ = 23.67 m
<h2>Answer</h2>
Radius is 421 m.
<u>Explanation </u>
A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,
As mass = m = 1500kg,
Centripetal force = Fc = 640N,
Velocity = v = 13.4 m / s
By putting values, Fc = mv ^ 2 / r,
r = mv ^ 2 / Fc,
=> r = ( 1500kg ) . ( 13.4 m / s) ^ 2 / 640,
=> r = ( 1500kg ) . ( 179.56 ) / 640,
r = 269340 / 640,
=> r = 420.84 m.
Radius is 421 m.
Answer:
The electric field inside the wire will remain the same or constant, while the drift velocity will by a factor of four.
Explanation:
Electron mobility, μ = 
where
= Drift velocity
E = Electric field
Given that the electric field strength = 1.48 V/m,
Therefore since the electric potential depends on the length of the wire and the attached potential difference, then when the electron mobility is increased 4 times the Electric field E will be the same but the drift velocity will increase four times. That is
4·μ = 
Answer:
6.0 s
98 m/s
Explanation:
The radius of the planet is much bigger than the height of the tower, so we will assume the acceleration is constant. Neglect air resistance.
Acceleration due to gravity on this planet is:
a = GM / r²
a = (6.67×10⁻¹¹ m³/kg/s²) (2.7 × 1.48×10²³ kg) / (1.7 × 750,000 m)²
a = 16.4 m/s²
The height of the tower is:
Δy = 96 × 3.05 m
Δy = 293 m
Given v₀ = 0 m/s, find t and v.
Δy = v₀ t + ½ at²
(293 m) = (0 m/s) t + ½ (16.4 m/s²) t²
t = 6.0 s
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (16.4 m/s²) (293 m)
v = 98 m/s
