Question

What is the mass of 4.67 mol of Sulfuric Acid (H2SO4)

Answer 1

Answer:

458 g H₂SO₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

4.67 mol H₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 3: Convert

1. Set up:                              $\displaystyle 4.67 \ mol \ H_2SO_4(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4})$
2. Multiply/Divide:                $\displaystyle 458.08 \ g \ H_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

458.08 g H₂SO₄ ≈ 458 g H₂SO₄