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3 years ago

1.- OBTENER LA ECUACION DE LA CIRCUNFERENCIA, QUE PASA POR EL PUNTO,

Mathematics

1 answer:

GrogVix [38]3 years ago

7 0

Answer:

i dont speak that language l m a o

Step-by-step explanation:

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Point R is at (3, 1.3) and Point T is at (3, 2.4) on a coordinate grid. The distance between the two points is _____.

Bond [772]

Answer:

d = 1.1 units

Step-by-step explanation:

Since the x- coordinates of the 2 points are equal, both 3, then they lie on a vertical line. The distance between the 2 points is the difference in the y- coordinates, that is

d = | 2.4 - 1.3 | = | 1.1 | = 1.1 units

7 0

2 years ago

Read 2 more answers

Write the number that can be shown with this many hundreds, tens and ones

Anit [1.1K]

Answer:

How many hundreds, tens and ones are there?

then I can answer it!

Step-by-step explanation:

8 0

3 years ago

Guided Practice

Harrizon [31]

Answer:

Step-by-step explanation:

i can't find it

5 0

2 years ago

You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard devia

Akimi4 [234]

Answer:

673 people

Step-by-step explanation:

Statistics<3

Use the margin of error formula.

ME = t* $\frac{s}{\sqrt{n} }$

Margin of error or ME = 3
Critical t or t* with a confidence level of 95% on the calculator is invNorm(.975) = 1.96. You would use invt, except you don't have the degrees of freedom, so you can approximate with invNorm. It's close enough.
Standard deviation or s = 39.7
Solve for n!

3 = 1.96* $\frac{39.7}{\sqrt{n} }$

3/1.96 = $\frac{39.7}{\sqrt{n} }$

1.531 = $\frac{39.7}{\sqrt{n} }$

39.7/1.531 = $\sqrt{n}$

25.937 = $\sqrt{n}$

25.937^2 = $\sqrt{n}$ ^2

672.7 = n

You need at least 673 people to be confident!

4 0

2 years ago

System of equations x-y-2z=4, -x+2y+z=1, x+y-3z=11. Solve by elimination

Wittaler [7]

$x-y-2z=4 \\ -x+2y+z=1 \\ x+y-3z=11 \\ \\ \left \{ {{x-y-2z=4 } \atop {-x+2y+z=1}} \right \ and \ \left \{ {{-x+2y+z=1 } \atop {x+y-3z=11}} \right \\ \\ \hbox{1st system:} \\ x-y-2z=4 \\ \underline{-x+2y+z=1} \\ x-x+2y-y-2z+z=4+1 \\ y-z=5$

$\hbox{2nd system:} \\ -x+2y+z=1 \\ \underline{x+y-3z=11} \\ x-x+2y+y-3z+z=1+11 \\ 3y-2z=12 \\ \\ \hbox{now compare both:} \\ y-z=5 \ \ \ |\cdot (-2) \\ 3y-2z=12 \\ \\ -2y+2z=-10 \\ \underline{3y-2z=12 \ \ \ \ \ \ } \\ 3y-2y+2z-2z=12-10 \\ y=2 \\ \\ 2-z=5 \\ -z=3 \\ z=-3 \\ \\ x-2-2 \cdot (-3) = 4 \\ x-2+6=4 \\ x+4=4 \\ x=0$

The answer is: x=0, y=2, z=-3.

3 0

2 years ago