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andrew11 [14]
3 years ago
15

A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​

Physics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

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You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4
lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy E=1.25\times10^{4}\ J

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

Q=mc\Delta T

c=\dfrac{Q}{m\Delta T}

Where, m = mass

c = specific heat

\Delta T = temperature

Q = heat

Put the value into the formula

c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}

c=14.8\ J/kg. K

Hence, The samples specific heat is 14.8 J/kg.K

8 0
3 years ago
A soap bubble, when illuminated at normal incidence with light of 463 nm, appears to be especially reflective. If the index of r
Sedbober [7]

Answer:

the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

Explanation:

Given the data in the question;

wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m

Index of refraction; n = 1.35

Now, the thinnest thickness of the soap film can be determined from the following expression;

t_{min = ( λ / 4n )

so we simply substitute in our given values;

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = ( 463 × 10⁻⁹ m ) / 5.4

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = 8.574 × 10⁻⁸ m

t_{min = 85.74 × 10⁻⁹ m

t_{min = 85.74 nm

Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

5 0
2 years ago
What are the methods of avoiding demagnetization​
lbvjy [14]

\\

The best method to use in prevention of self-demagnetization of a permanent magnet is by use of a keeper. Keepers were also commonly known as amateurs. They help in storing magnets safely, especially those that have low coercivity ( magnets that are extremely susceptible to stray fields).

\\

Hope It Helps!

4 0
3 years ago
A 3.0 \Omega Ω resistor is connected in parallel to a 6.0 \Omega Ω resistor, and the combination is connected in series with a 4
GarryVolchara [31]

Answer:

The power dissipated in the 3 Ω resistor is P= 5.3watts.

Explanation:

After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.

The resultating resistor is of Req=6Ω.

I= V/Req

I= 2A

the parallel resistors have a potential drop of Vparallel=4 volts.

I(3Ω) = Vparallel/R(3Ω)

I(3Ω)= 1.33A

P= I(3Ω)² * R(3Ω)

P= 5.3 Watts

7 0
3 years ago
How does cancer change the normal life cycle of a cell ?
melamori03 [73]

In normal cells, the cell cycle is controlled by a complex series of signaling pathways by which a cell grows, replicates its DNA and divides.

In cancer, as a result of genetic mutations, this regulatory process malfunctions, resulting in uncontrolled cell proliferation.

4 0
3 years ago
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