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mixas84 [53]
1 year ago
14

You need a 450 microgram sample of gold, but you only have a mass balance that measures in decigrams. Convert the amount of gold

you need to decigrams by comparing the exponents. Provide your answer in scientific notation. Be sure to show your work.
Physics
1 answer:
sveta [45]1 year ago
7 0

The amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.

<h3>How to convert micrograms to decigrams?</h3>

According to this question, 450 micrograms of a sample of gold is needed but we only have a mass balance that measures in decigrams.

This means that we are to convert the amount of gold you need to decigrams by comparing the exponents.

The conversion factor of micrograms to decigrams is as follows:

1 micrograms = 1 × 10-⁵ decigrams

This means 450 micrograms is equivalent to 450 × 1 × 10-⁵ = 4.5 × 10-³ decigrams

Therefore, the amount of gold in decigrams if 450 micrograms is needed is 4.5 × 10-³ decigrams.

Learn more about decigrams at: brainly.com/question/6869599

#SPJ1

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3 years ago
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7 0
2 years ago
b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?​
umka2103 [35]

Answer:

Twice.

Explanation:

The momentum of an object is given by :

p = mv

Where

m is mass and v is the velocity

If the mass of the ball were doubled, m'=2m and v'=v=3 m/s

New momentum,

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6 0
2 years ago
A transformer consists of 290 primary windings and 824 secondary windings. Part A: If the potential difference across the primar
jasenka [17]

Answer:

Part 1) Voltage in secondary windings is 61.08 Volts

Part 2) Current in secondary windings is 0.53 Amperes

Explanation:

The potential developed in the primary and secondary winding of a transformer are related as

\frac{N_{p}}{N_{s}}=\frac{V_{p}}{V_{s}}

where

Np no of turns in primary coil

Ns no of turns in secondary coil

Vp Voltage of turns in primary coil

Vs Voltage of turns in secondary coil

Applying values in the formula we get

\frac{290}{824}=\frac{21.5}{V_{s}}\\\\\therefore V_{s}=21.5\times \frac{824}{290}=61.08V

Part 2)

Using Ohm's law the current is given by

I=\frac{V_{s}}{R}\\\\I=\frac{61.089}{115}=0.53A

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3 years ago
In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular
Darya [45]

Answer:

40.91 m/s

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w = angular velocity of the ball about the elbow joint = 30.3 rad/s

r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m

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Linear velocity of the ball is given as

v = r w

Inserting the values given above in the equation

v = (1.35) (30.3)

v = 40.91 m/s

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3 years ago
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