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Alik [6]
2 years ago
6

Working with one sample at a time, add water to the glass one tablespoon at a time. Water should soak the sample from the bottom

up. Count the number of tablespoons of water it takes to bring the water level up to the top of the sample. Record the amount in the chart.
Calculate the porosity of each sample using this formula, and record the results in the table. “Total sample volume” is the amount of soil, sand, or pebbles in the sample. A half cup is equal to 8 tablespoons.
% porosity = (amount of water added to sample ÷ total sample volume) × 100

PEBBLES -

SAND -

SOIL -
Chemistry
1 answer:
Leokris [45]2 years ago
6 0

Answer:

1. Fill a drinking glass with a cup of water (1 cup =237 ml). Add sugar one teaspoon at a time until you have added 5 teaspoons. Stir and wait until each teaspoon dissolves completely. Between each teaspoon, take a sip and see how “the drink” tastes. After 5 teaspoons you will have added ~ 25 grams, i.e. slightly less than there is in one cup of coca-cola. After how many teaspoons is the drink pleasantly sweet? After how many teaspoons is it way too sweet?

2. Pour half of the sugar-water into a separate drinking class and put it aside for later.

3. To the remaining sugar water solution (~1/2 cup), add small amounts of vinegar, approximately 1/4 teaspoon at a time, taking a small taste after each addition. Keep track of how much vinegar you are adding. How much did you have to add for the drink to taste good to you? Put this glass aside for later comparison.

4. Now fill another drinking glass with half a cup of water (1/2 cup =120 ml), and add the same amount of vinegar that you added to the sugar-water in step 3 in order for it to taste delicious. In other words, you will now have three cups: one with sugar-water, one with sugar-vinegar-water, and one with vinegar-water. Have a taste of the vinegar-water. How does the vinegar-water taste compared to the sugar-vinegar-water drink? To the sugar-water drink?

This is the secret of Coca-Cola! Coca-cola contains a lot of sugar, probably way too much for most people to find tasty. But by adding acid (and some other flavors as well) you can get a tasty drink!

This is an example of the complex ways in which taste molecules can influence each other, and recipes often exploit this fact. By having different flavors play off each other, the crafty cook can adjust the overall flavor experience of a food. This is a similar reason to why some cooks add a bit of sugar to balance out the acidity of tomatoes in a tomato sauce. And Nathan Myhrvold, whom we will hear from later in this course, even goes so far as to add salt to red wine to make it taste better!

Questions:

1. Calculate how many moles of sugar per liter you added to your drink in step 1 before starting to add any vinegar. The molecular weight of sugar (i.e., sucrose) is 342 g/mol, and 1 teaspoon corresponds to approximately 5 grams. Enter your answer to two decimal places, and do not include units.

Teapoons pH 1/4 4.5 2x 1/4 4.2 3x 1/4 4.0 4x 1/4 3.9 5x 1/4 3.8 6x 1/4 3.7 7x 1/4 3.7 8x 1/4 3.6 9x 1/4 3.6 10x 1/4 3.5

2. Calculate the concentration of hydrogen ions in moles per liter in your drink after you added 1.5 tsp of vinegar. You can use the table above which approximates the pH when adding certain amounts of vinegar to water. Enter your answer to one non-zero digit, and do not include units.

 unanswered

3. How many times more sugar molecules are there than hydrogen ions in this drink?

Show detailed calculations and sketches to solve problems, we will get similar problems for the final exam. thank you!!!

Explanation:

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Look up and record the boiling point of acetic acid, and explain why only some of it evaporates from the reaction mixture.
REY [17]

Answer:

Heating the mixture to a temperature above the boiling point of acetic acid, but below 100°C (the boiling point of water). The vapours from the acetic acid rise, and go into a tube. They are then condensed within the tube, and run off into a separate storage area. Because water can exist as a gas at pretty much any temperature above 0°C, it will result in an impure mixture, but repeatedly doing this will get the acetic acid to the desired purity.

8 0
3 years ago
Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce
OLga [1]
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!
4 0
3 years ago
What term refers to the period of life from puberty to the end of the teenage years?
Daniel [21]
A - adolescence.
 
According to google definitions..

Adolescencenounthe period following the onset of puberty during which a young person develops from a child into an adult.
7 0
3 years ago
Which of the following is an example of an experimental scientific investigation
sleet_krkn [62]

Scientific investigation is the process in which scientist solve the problems by using different systematic approach. It can be initiated in different ways.

Experimental Scientific investigation: The investigation in which scientist answer the question on the basis of experimental results. Experimental investigation contains both dependent and independent variables, and only one variable is tested at a time is possible. This process makes uses of collecting observation and identifying the process in physical word.

Noting the colour of a solution when heated is the experimental scientific investigation

Therefore, other given options are part of scientific observation whereas Noting the colour of a solution when heated explains the experimental scientific investigation.



7 0
3 years ago
Read 2 more answers
Calculate the theoretical yield and percent yield for this experiment
coldgirl [10]

Answer:

A. Theoretical yield of KCl is 36.49g

B. Percentage yield of KCl is 90.4%

Explanation:

The balanced equation for the reaction is given below:

2KCLO3 —> 2KCl + 3O2

Next, we shall determine the mass KClO3 that decomposed and the mass KCl produce from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Molar mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g.

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

A. Determination of the theoretical yield of KCl. This is illustrated below:

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

Therefore, 60g of KClO3 will decompose to produce = (60 x 149)/245 = 36.49g of KCl.

Therefore, the theoretical yield of KCl is 36.49g

B. Determination of the percentage yield of KCl. This can be obtaine as follow:

Actual yield = 33g

Theoretical yield = 36.49g

Percentage yield =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 33/36.49 x 100

Percentage yield of KCl = 90.4%

7 0
3 years ago
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