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Lilit [14]
3 years ago
8

P5-F2 + Ar --> ArF3

Chemistry
1 answer:
anzhelika [568]3 years ago
8 0

Answer:

5a. 13.5 moles of F₂

5b. 3.33 moles of Ar.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3F₂ + 2Ar —> 2ArF₃

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.

5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of ArF₃.

Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e

Xmol of F₂ = (3 × 9)/2

Xmol of F₂ = 13.5 moles

Thus, 13.5 moles of F₂ is needed.

5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar.

Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.

Thus, 3.33 moles of Ar was consumed.

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The composition of a compound is 20.01% carbon and 79.99% oxygen by mass. what is its empirical formula?
Anni [7]
Assume there are 100g of the compound.
Mass of carbon:20.01g
Mass of oxygen:79.99g
Number of mole of carbon:20.01/12=1.6675mol
Number of mole of oxygen:79.99/32=2.4996875mol
Mole ratio between carbon and oxygen:
1.6675/1.6675:2.4996875/1.6675
=1:1.499062969
1x2:1.499062969x2
=2:2.998125937
≈2:3
Hence, the empirical formula:
C2O3
5 0
3 years ago
If a person weighs 87lbs and has to be given a drug with a dosage of 50 milligrams per kilogram body weight, how many grams of t
Katarina [22]

Answer:

1 957,5

Explanation:

87libs=39.5kg that equals 50=1.957.5

7 0
3 years ago
Is gunpowder a homogenous mixture or a heterogenous mixture? Explain why.
inysia [295]

Gunpowder is a heterogenous mixture,

Reason : the composiotion of the mixture is not uniform throughout, the mixture can be separated by a suitable method , and finally , it composes of charcoal, sulfur and potassium nitrate which is not homogeneous mixture.

4 0
1 year ago
In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is
GaryK [48]

Answer:

Attached below

Explanation:

Free energy of mixing = ΔGmix = Gf - Gi

attached below is the required derivation of the

<u>a) Molar Gibbs energy of mixing</u>

ΔGmix = Gf - Gi

hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )

<u>b) molar excess Gibbs energy of mixing</u>

Ni = chemical potential of gas

fi = Fugacity

N°i = Chemical potential of gas when Fugacity = 1

ΔG = RT In ( a2 / a1 )  

4 0
3 years ago
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
3 years ago
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