Answer:
5a. 13.5 moles of F₂
5b. 3.33 moles of Ar.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3F₂ + 2Ar —> 2ArF₃
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.
5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of ArF₃.
Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e
Xmol of F₂ = (3 × 9)/2
Xmol of F₂ = 13.5 moles
Thus, 13.5 moles of F₂ is needed.
5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar.
Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.
Thus, 3.33 moles of Ar was consumed.
