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3 years ago

P5-F2 + Ar --> ArF3

Chemistry

1 answer:

anzhelika [568]3 years ago

8 0

Answer:

5a. 13.5 moles of F₂

5b. 3.33 moles of Ar.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3F₂ + 2Ar —> 2ArF₃

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.

5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of ArF₃.

Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e

Xmol of F₂ = (3 × 9)/2

Xmol of F₂ = 13.5 moles

Thus, 13.5 moles of F₂ is needed.

5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar.

Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.

Thus, 3.33 moles of Ar was consumed.

You might be interested in

How many molecules in 9.18 moles of C11H12O22

Setler [38]

Answer:

55.3 × 10²³ molecules

Explanation:

Given data:

Number of moles of C₁₁H₁₂O₂₂ = 9.18 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given data:

9.18 mol × 6.022 × 10²³ molecules /1 mol

55.3 × 10²³ molecules

5 0

3 years ago

For 2,663 kg of a compound with the formula Al(SO), determine the following quantities (4 pts each); a) The number of moles of t

Nastasia [14]

Answer:

a) 35.485 moles of Al(SO)

b) 35.485 moles of S atoms

c) $2.136197(10^{25})$ Al atoms

d) 567.723 g of O

Explanation:

Let's define the following terms :

1 mol = $6.02.(10^{23})$ elemental units

For example :

1 mol of oxygen atoms = $6.02.(10^{23})$ oxygen atoms

Now, our compound has the following formula

Al(SO)

Where Al is aluminium

S is sulfur

And O is oxygen

All the subscripts are 1 so we can say the following :

1 molecule of Al(SO) has 1 atom of Al , 1 atom of S and 1 atom of O

In terms of moles :

1 mol of Al(SO) has 1 mol of Al , 1 mol of S and 1 mol of O

The molar masses of Al, S and O are

$molarmass_{(Al)}=26.982\frac{g}{mol}$

$molarmass_{(S)}=32.065 \frac{g}{mol}$

$molarmass_{(O)}=15.999\frac{g}{mol}$

If we sum all the molar masses = $(26.982+32.065+15.999)\frac{g}{mol}=75.046\frac{g}{mol}$

Finally, 75.046 g of Al(S0) is 1 mol of Al(SO) which contains 26.982 g of Al, 32.065 g of S and 15.999 g of O.

1 mol of Al(SO) contains 1 mol of Al, 1 mol of S and 1 mol of O.

Now we can calculate a),b),c) and d)

For a)

$2.663 kg=2663g$

75.046 g of Al(SO) = 1 mol of Al(SO)

2663 g of Al(SO) = x

$x=\frac{2663}{75.046}mol=35.485 mol$

2.663 kg of Al(SO) contains 35.485 moles of Al(SO)

b) and c) 1 mol of Al(SO) molecules contains 1 mol of S atoms and 1 mol of Al atoms

We have 35.485 moles of Al(SO) molecules so

We have 35.485 moles of S atoms

And 35.485 moles of Al atoms

If 1 mol = $6.02(10^{23})$

35.485 moles of Al have $(35.485)(6.02)(10^{23})=2.136197(10^{25})$ Al atoms

d) 75.046 g of Al(SO) contains 15.999 g of O

2663 g of Al(SO) contains x g of O

$x=\frac{(2663).(15.999)}{75.046} g$

x = 567.723 g of O

6 0

3 years ago

Calculate the number of atoms

ra1l [238]

D.....................

5 0

2 years ago

In this reaction, what is the correct coefficient for hydrogen gas? ? h2 + ? o2 ? ? h2o

iragen [17]

To balance a chemical reaction, it is important to remember that the number of atoms of each element in the reactants and the product side should be equal. This is to follows the law of conservation of mass where mass cannot be created or destroyed. So, the total mass that is used to react should have the same value of the total mass of the substances produced from the reactants. The balanced chemical reaction would be written as follows:

<span> 2h2 + o2 = 2h2o

Reactant = Product
H = 4 = 4
O = 2 = 2

Therefore, the correct coefficient for the hydrogen gas would be 2.</span>

6 0

2 years ago

Student have a receipt which calls for 1.15 lb of flour, but, of course, in France you will need to purchase flour in kilograms.

Verizon [17]

0.52164 kg of Flour

<u>Explanation:</u>

We have to convert lb (pounds) kg (kilograms), by using the conversion unit,

1 lb = 0.4536 kg

So to convert 1.15 lb into kg, we have to multiply 1.15 by 0.4536.

$1.15 \times 0.4536$ = 0.52164 kg of Flour

So the receipt calls for 0.52164 kg of Flour.

5 0

3 years ago