New York has a density of millionaires more than twice that of the country as a whole. The density of millionaires is about the same for New York City as for the United States. Millionaires seem to prefer New York City to much of the rest of the United States. There is something in the water of New York City that encourages millionaires
ANSWER
B) A rectangle with a length of 15 cm and a width of 9 cm.
EXPLANATION
The given rectangle, A, has length, 10cm and its width is 6cm.
The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.
For option A, the triangle has length 9cm and width 6cm.
The ratio of the corresponding sides are:

Since the ratios are not equal, the two triangles are not similar.
For the triangle in option B, the length is 15cm and the width is 9cm.
The ratio of the corresponding sides are:

Since the sides of the triangle are in the same proportion, the two triangles are similar.
For option C, the proportions are not the same.

The proportions are not the same for the triangle in option D.
EDIT:
2x + 0.75 = 13
Add like terms
2x= 13-0.75
2x= 12.25
x= 12.25/2
x=6.125
You can buy 6 whole shirts with $0.25 left over
Hope this helps! A thanks/brainliest answer would be appreciated :)
Answer:
Length of diagonal is 7.3 yards.
Step-by-step explanation:
Given: The diagonal distance from one corner of the corral to the opposite corner is five yards longer than the width of the corral. The length of the corral is three times the width.
To find: The length of the diagonal of the corral.
Solution: Let the width of the rectangular garden be <em>x</em> yards.
So, the length of the diagonal is 
width of the rectangular corral is 
We know that the square of the diagonal is sum of the squares of the length and width.
So,







Since, side can't be negative.

Now, length of the diagonal is
Hence, length of diagonal is 7.3 yards.
Answer:
b. (1, 3, -2)
Step-by-step explanation:
A graphing calculator or scientific calculator can solve this system of equations for you, or you can use any of the usual methods: elimination, substitution, matrix methods, Cramer's rule.
It can also work well to try the offered choices in the given equations. Sometimes, it can work best to choose an equation other than the first one for this. The last equation here seems a good one for eliminating bad answers:
a: -1 -5(1) +2(-4) = -14 ≠ -18
b: 1 -5(3) +2(-2) = -18 . . . . potential choice
c: 3 -5(8) +2(1) = -35 ≠ -18
d: 2 -5(-3) +2(0) = 17 ≠ -18
This shows choice B as the only viable option. Further checking can be done to make sure that solution works in the other equations:
2(1) +(3) -3(-2) = 11 . . . . choice B works in equation 1
-(1) +2(3) +4(-2) = -3 . . . choice B works in equation 2