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kolezko [41]
3 years ago
8

Which action would shift this reaction away from solid barium sulfate and toward the dissolved ions?

Chemistry
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

   adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.

Explanation:

Barium sulfate is an insoluble ionic  compound since it is insoluble in water.

We can differentiate barium ions and sulfate ions away from the surface if we add a small amount of solid barium sulfate is mixed with water and shaken.

  The action would shift this reaction away from solid barium sulfate and toward the dissolved ions are adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.

An ionic and covalent quality has in every molecular bond.

In barium sulfate barium has lowest electronegativities.

Oxygen has highest electronegativities.

so the bond between both barium and sulfate is ionic in character.

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Neko [114]

Pushing(Compression) Causes the faults and folds


3 0
4 years ago
Some one please help me name the following compound CsCrO4​
lozanna [386]

Answer:

Cs is cesium and CrO₄ is chromate so CsCrO₄ is cesium chromate.

8 0
3 years ago
The pka of hf is 3.2 determine the pkb of hf?
Julli [10]

Well, first we must remember that

pK_{a}+pK_{b}=14

This is because

K_{a}*K_{b}=10^{-14}

-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14

So then

pK_{b}=14-pK_{a}=14-3.2=1.8

7 0
4 years ago
Read 2 more answers
What effect does increasing the concentration of a dissolved solute have on each of the colligative properties?
Igoryamba

Answer:

If we increase the concentration of a dissolved solute, the solution would have a vapor pressure so much low, the boiling temperature for the solution will be so high, freezing point for the solution will be so much low and the osmotic pressure will be higher.

Colligative properties always depends on dissolved particles (solute)

Explanation:

These are the colligative properties

- Vapor pressure lowering

ΔP = P° . Xm

Vapor pressure of pure solvent - Vapor pressure of solution.

If we add more solute, it would raise the Xm, so the solution would have a vapor pressure so much low.

Vapor pressure pure solvent - Vapor pressure solution ↑ = P° . Xm ↑

- Boiling point elevation

ΔT = Kb . m

When we add more solute, we are increasing the molality.

↑T° boiling of solution - T° boiling pure solvent = Kf . m ↑

Boiling temperature for the solution will be so high.

- Freezing point depression

When we add more solute, we are increasing the molality.

ΔT = Kf . m

T° fussion of pure solvent - ↓T° fussion of solution = Kf . m↑

Freezing point for the solution will be so much low.

- Osmotic pressure

π = M . R . T

When we add solute, molarity is increasing. Therefore the osmotic pressure will be higher.

π↑ = M↑ . R . T

7 0
3 years ago
a doctor's order is 0.125 g of ampicillin. the liquid suspension on hand contains 250 mg/5.0 ml. how many milliliters of the sus
disa [49]
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.

Then, we need 125 mg of ampicillin.
5 ml of  liquid suspension contains 250 mg of ampicilling , therefore:

5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling

x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml

Answer: we require 2.5 ml
5 0
4 years ago
Read 2 more answers
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