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2 years ago

I WILL MARK BRAINLIEST TO WHOEVER GETS THIS CORRECT

Physics

2 answers:

Veseljchak [2.6K]2 years ago

6 0

Answer:

If south-east Texas is where H then it is C, but if not the answer is A.

elena-14-01-66 [18.8K]2 years ago

3 0

Answer:

b or c pretty sure its b b tho

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A real spring does not oscillate forever. Instead, it eventually comes to a stop. Does this violate the law of conservation of e

ss7ja [257]

It does not violate the law of conservation of energy. The oscillation stops when the energy is lost and the energy is lost because it becomes heat that is created by the air resistance and many other forces found in the surrounding of the oscillating spring.

5 0

3 years ago

Why do planets rings surround them and not the sun

Shalnov [3]

Well, the rings surrounding a planet are made out of rock. A ring surrounding the sun would be impossible since the sun can reach more than 27 million degrees Fahrenheit (15 million degrees Celsius.)

Hope this helped.

7 0

3 years ago

Janet ran 30 meters in 4 seconds,what is her speed.

lubasha [3.4K]

Answer:

7.5 meters per second

Explanation:

30 / 4 = 7.5

7.5 * 1 = 7.5

7.5 * 2 = 15

7.5 * 3 = 22.5

7.5 * 4 = 30

8 0

3 years ago

Read 2 more answers

radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the

Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

$v = 3 \times 10^8 m/s$

the altitude of the airplane is given as

$h = 1 \times 10^4 m$

now we know that time taken by the signal to reach the control tower is given as

$t = \frac{d}{v}$

now it is given as

$t = \frac{1 \times 10^4 }{3 \times 10^8}$

$t = 3.33 \times 10^{-5} s$

so above is the time taken by the signal to reach the control tower

3 0

3 years ago

A cart moving at 10 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the a

Elena L [17]

Answer:

Impulse = 88 kg m/s

Mass = 8.8 kg

Explanation:

<u>We are given a graph of Force vs. Time. Looking at the graph we can see that the Force acts approximately between the time interval from 1sec to 4sec. </u>

Newton's Second Law relates an object's acceleration as a function of both the object's mass and the applied net force on the object. It is expressed as:

$F=ma$ Eqn. (1)

where

$F$ : is the Net Force in Newtons ( $N$ )

$m$ : is the mass ( $kg$ )

$a$ : is the acceleration ( $m/s^2$ )

We also know that the acceleration is denoted by the velocity ( $v$ ) of an object as a function of time ( $t$ ) with

$a=\frac{v}{t}$ Eqn. (2)

Now substituting Eqn. (2) into Eqn. (1) we have

$F=m\frac{v}{t}\\ \\Ft=mv$ Eqn. (3)

However since in Eqn. (3) the time-variable is present, as a result the left hand side (i.e. $Ft$ is in fact the Impulse $J$ of the cart ), whilst the right hand side denotes the change in momentum of the cart, which by definition gives as the impulse. Also from the graph we can say that the Net Force is approximately ≈ $22N$ and $t=4 sec$ (thus just before the cut-off time of the force acting).