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2 years ago

Calculate the kinetic energy of a .30 kg ball thrown at a velocity of 96.6 m/hr in J.

Physics

1 answer:

spin [16.1K]2 years ago

4 0

Answer:

1.08 x 10^-4 J

Explanation:

mass of ball, m = 0.3 kg

Velocity of ball, v = 96.6 m/hr

First convert m/hr into m/s.

As we know that 1 hour = 3600 second

So, 96.6 m / hr = 96.6 / 3600 m/s = 0.0268 m/s

The formula for the kinetic energy is given by

Kinetic energy = 1/2 mv^2

Kinetic energy = 0.5 x 0.3 x 0.0268 x 0.0268 = 1.08 x 10^-4 J

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A mass m0 is attached to a spring and hung vertically. The mass is raised a short distance in the vertical direction and release

iragen [17]

Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

E xplanation:

T= $2pie\frac sqrt {m}{k}$

$\frac {{f2}/times {fo}}$ =1:3

⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

⇒ $\frac{f2} {f1}$ = $\frac sqrt{m1}[m2}$

⇒ $\frac{f2}{fo}$ = 1:3

⇒f2= $\frac{fo} {3}$

6 0

2 years ago

A car with a mass of 1100kg is moving in a circular curve at a uniform velocity of 15m/s

Dmitrij [34]

Centripetal force = (mv^2)/r
so r = (mv^2)/ force = 246500 / 1100 = 224 m

7 0

2 years ago

A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a

hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

$a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2$

So the magnitude of the total acceleration is

$a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2$

4 0

3 years ago

If the average gauge pressure in the vein is 12200 Pa, what must be the minimum height of the bag in order to infuse glucose int

Amanda [17]

Answer:

h = 1.22 m

Explanation:

Given:

Pressure in the vein = 12200 Pa

Specific gravity of the liquid = 1.02

now,

the pressure due to a fluid is given as:

P = pgh

where,

P is the pressure,

ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³

ρ = 1020 kg/m³

g is the acceleration due to the gravity = 9.81m/s²

h is the height

thus,

h = P/pg = $\frac{12200}{1020\times 9.8}=1.22 m$

6 0

2 years ago

A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th

lianna [129]

Answer:

$F_n = 7509.33\ N$

Explanation:

given,

radius of curve = 166 m

angle of the banked road = 11°

mass of car = 736 Kg

speed of the curve = 81 km/h

= 81 x 0.278 = 22.52 m/s

normal force acting on the tires

on tire there will be two force acting on it

first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.

$F_n = m g cos \theta+ \dfrac{mv^2}{r} sin \theta$

$F_n = 736 \times 9.8 \times cos 11^0+\dfrac{736 \times 22.52^2}{166} sin 11^0$

$F_n = 7080.28+429.047$

$F_n = 7509.33\ N$

6 0

3 years ago