Answer:
The frequency of the oscillations in terms of fo will be f2=fo/3
E xplanation:
T= 
=1:3
⇒f2=fo\3
Here frequency f is inversely poportional to square root of mass m.
so the value of remainder of frequency f2 and fo is equal to 1:3.
⇒
= 
⇒
= 1:3
⇒f2=
Centripetal force = (mv^2)/r
so r = (mv^2)/ force = 246500 / 1100 = 224 m
Answer:
5 m/s2
Explanation:
The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.
The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

So the magnitude of the total acceleration is

Answer:
h = 1.22 m
Explanation:
Given:
Pressure in the vein = 12200 Pa
Specific gravity of the liquid = 1.02
now,
the pressure due to a fluid is given as:
P = pgh
where,
P is the pressure,
ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³
ρ = 1020 kg/m³
g is the acceleration due to the gravity = 9.81m/s²
h is the height
thus,
h = P/pg =
Answer:

Explanation:
given,
radius of curve = 166 m
angle of the banked road = 11°
mass of car = 736 Kg
speed of the curve = 81 km/h
= 81 x 0.278 = 22.52 m/s
normal force acting on the tires
on tire there will be two force acting on it
first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.



