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2 years ago

For two consecutive numbers, five times the number that is less is 3 more than 4 times the greater number, What are the numbers

Mathematics

1 answer:

Gemiola [76]2 years ago

5 0

Answer:

smaller number - 7

greater number - 8

Step-by-step explanation:

let a = smaller number

a + 1 = greater number

the following equation can be derived from the question

(5 x a) = 3 + 4(a + 1)

5a = 3 + 4a + 4

5a = 7 + 4a

5a - 4a = 7

a = 7 = smaller number

a + 1 = 7 + 1 = 8 = greater number

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Joseph and Wendy were catching tadpoles. At first Wendy caught nine times three more than Joseph caught. Joseph was upset and re

Dmitriy789 [7]

Answer:

Joseph caught 7 tadpoles

Step-by-step explanation:

Let the number of tadpoles caught by Joseph be x

The number of tadpoles Wendy caught will be ;

9(x + 3)

After Joseph was upset, he released half of Wendy’s tadpole and then six times as many as Joseph caught swam away leaving Wendy with only three tadpoles left;

Hence, mathematically;

9(x + 3)/2 - 6x = 3

Multiply through be 2

9(x + 3) - 12x = 6

9x + 27 -12x = 6

9x -12x = 6-27

3x = 21

x = 21/3

x = 7

6 0

3 years ago

What's the recursive formula of the geometric sequence below?

yKpoI14uk [10]

Answer:

Hey there!

We have an=a1(r^n-1), which is the formula for a geometric sequence.

The common ratio is 3, and 2 is the 1st term.

Thus, we have a1=2(3)^(n-1)

Hope this helps :)

5 0

3 years ago

Help ASAP!!!!! I need ittt

ivann1987 [24]

Answer:

I believe the answer ur looking for is 3 (D)

Step-by-step explanation:

5 0

2 years ago

Need help with number 3 inequalities with variables on both sides

Volgvan

Answer:

x ≤ 2

Step-by-step explanation:

We are given the inequality:

$\displaystyle{2x-3 \leq \dfrac{x}{2}}$

First, get rid of the denominator by multiplying both sides by 2:

$\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}$

Add both sides by 6 then subtract both sides by x:

$\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}$