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MArishka [77]
3 years ago
13

A group of engineers has created a biodome filled with air, plants, and animals. No material can get in or out, but sunlight can

get in during the daytime.
The walls of the biodome are made of a material that absorbs and locks away carbon dioxide from the air so it is not available to the living things inside. What do you predict will happen to carbon in the air over time? How could this affect the living things in the dome? Explain your thinking.
Chemistry
1 answer:
trapecia [35]3 years ago
6 0
Thx for the points lol
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You are asked to prepare 500. mL of a 0.200 M acetate buffer at pH 5.10 using only pure acetic acid (MW=60.05 g/mol, pKa=4.76),
Alenkasestr [34]

Answer:

1. 6.005 g

2. 22.9 mL

3. Until the mixtures becomes homogeneous.

Explanation:

A buffer is a solution where a weak acid is in equilibrium with its conjugate base (its anion) or a weak base is in equilibrium with its conjugate base (its cation). The buffer remains the pH almost unaltered because it shifts the equilibrium if an acid or base is added.

1. The pH of a buffer can be calculated by the Henderson-Hasselbalch equation:

pH = pKa + log[A⁻]/[HA]

Where [A⁻] is the concentration of the conjugate base (the anion) of the acid, and HA is the acid concentration.

5.10 = 4.76 + log[A⁻]/[HA]

log[A⁻]/[HA] = 5.10 - 4.76

log[A⁻]/[HA] = 0.34

[A⁻]/[HA] = 10^{0.34}

[A⁻]/[HA] = 2.1878

Because the volume is the same, we can replace the concentration by the number of moles (n):

nA⁻/nHA = 2.1878

nA⁻ = 2.1878*nHA

The total number of moles of the substances in the buffer is: 0.200 mol/L * 0.5 L = 0.1 mol

nA⁻ + nHA = 0.1

2.1878*nHA + n HA = 0.1

3.1878nHA = 0.1

nHA = 0.0314 mol

nA⁻ = 0.0686 mol

The total number of moles of acetic acid needed is 0.1 mol (both substances may be from it):

m = MW*mol

m = 60.05*0.1 = 6.005 g

2. NaOH must react with acetic acid to form the anion, so for a 1:1 reaction, it will be needed 0.0686 mol of NaOH:

V = mol/concentration

V = 0.0686/3

V = 0.0229 L = 22.9 mL

3. The buffer must be a homogeneous solution, it means that it can't be noticed phases in the buffer, so the flask must be inverted until all the buffer is diluted in water, and it will be noticed when the solution becomes homogenous.

6 0
3 years ago
Reflecting and refracting telescopes are used to gather radiation from space. Which of these statements best explains why a refr
galben [10]
I think the correct answer from the choices listed above is option A. A refracting telescope is made smaller than a reflecting telescope because small lenses cause less distortion in images than big lenses. <span> They are not subject to chromatic aberration because reflected light does not disperse according to wavelength.</span>
6 0
3 years ago
Which three factor are most important in determining the composition of ocean water
lina2011 [118]
<span>There are factors that are important to be determined for the composition of ocean water. First factor is the temperatue, by this you will be able to know the rate of evaporation of the sea. Next is the salinity, through this you will be able to know salty the sea is which will help you identify the last factor- density. The density is the most common because when there is more salt in the sea, it is less dense.</span>
6 0
3 years ago
Read 2 more answers
A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh
Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C =  -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C =  4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0
3 years ago
What is molarity and how is it calculated? If possible, please explain it to me detailed. Thank you :)​
Lyrx [107]

Molarity is a concentration unit, defined to be the number of moles of solute divided by the number of liters of solution.

4 0
3 years ago
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