Answer:
0.3758moles
Explanation:
moles of kcl = mass of kcl/ molar mass of kcl = 28/74.5 = 0.3758moles
The correct option is this: THE CONCENTRATION OF THE PRODUCTS AND THE REACTANTS DO NOT CHANGE.
A reversible chemical reaction is said to be in equilibrium if the rate of forward reaction is equal to the rate of backward reaction. At this stage, the concentrations of the products and the reactants remain constant, that is, there is no net change in the concentration even though the reacting species are moving between the forward and the backward reaction.
Answer:
The concentration the student should write down in her lab is 2.2 mol/L
Explanation:
Atomic mass of the elements are:
Na: 22.989 u
S: 32.065 u
O: 15.999 u
Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.
Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.
For mole(s) of Na2S2O3 = (mass taken)/(molar mass)
= (17.240 g)/(158.105 g/mol) = 0.1090 mole.
Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)
= 0.05029 L.
To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:
= (moles of sodium thiosulfate)/(volume of solution in L)
= (0.1090 mole)/(0.05029 L)
= 2.1674 mol/L
Answer:
If the temperature of gas is decreased the pressure will also goes to decrease.
Explanation:
The pressure and temperature have direct relation. If the temperature of gas will increase the pressure of gas will also goes to increase.
According to the Gay-Lussas's Law,
The pressure of given amount of gas is directly proportional to the absolute temperature when volume is kept constant.
Mathematical relationship:
P ∝ T
P = kT
P/T = k
and
P₁/T₁ = P₂/T₂
Answer:
Option C = 6 of carbon react with 16 g of oxygen.
Explanation:
In given question it is stated that 12 g of carbon react with 32 g of oxygen to produce carbon dioxide. The other combination option c is also true because in this, the quantity of both reactant is just half from the given quantity. Which means that if 100 % product is obtained from the 12 g of carbon and 32 g of oxygen then by taking the half amount of reactant the product will be half i.e 50% .
This combination is true because the ratio of both reactant are justified.
Carbon 12g + Oxygen 32g → carbon dioxide
C : O 1 : 2.6
Option C:
Carbon ( 12/2 =6g ) + Oxygen (32/2 = 16g) → Carbon dioxide
C : O 1 : 2.6
