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STatiana [176]
3 years ago
6

What causes a star to shine brightly

Chemistry
1 answer:
asambeis [7]3 years ago
6 0

Answer:

Stars shine because they are extermly hot of light .The source of their energy is niclear reactions going on deep inside the stars.

Explanation:

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Through a process known as electrolysis, water can be split into hydrogen and oxygen. What type of reaction is this? Give an exp
AlexFokin [52]
Electrolysis of water<span> is the </span><span>decomposition reaction, because from one molecule (water) two molecules (hydrogen and oxygen) are produced. Water is separeted into two molecules:
</span>Reaction of reduction at cathode: 2H⁺(aq) + 2e⁻<span> → H</span>₂(g<span>).
</span><span><span>Reaction of oxidation at anode: 2H</span></span>₂<span><span>O(l) → O</span></span>₂<span><span>(g) + 4H</span></span>⁺(<span><span>aq) + 4e</span></span>⁻.<span><span>
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8 0
2 years ago
The density of red wine is 1.01g/cm3 and the density of olive oil is 0.92g/cm3.A salad dressing that consisted of these two ingr
Sauron [17]

the red wine is the densest so, it will be on bottom olive oil will be on the top. because its less than the red wine

3 0
3 years ago
Which description best characterizes the motion of particles in a solid?
Masja [62]

Answer:

D. Vibrating around fixed positions

Explanation:

It's right on edge

6 0
2 years ago
Is volume conserved​
svlad2 [7]

Answer:

no, volume isn't conserved

6 0
3 years ago
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
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