You have a point on a rectangular graph with coordinates (6, 8).
You want to describe the same location in polar coordinates ... R and Θ .
-- 'R' is the distance from the origin to the point.
-- 'Θ' is the angle you'd need to turn the x-axis counterclockwise
around the origin to make it pass through the point.
To change rectangular coordinates to polar coordinates:
R = √(x² + y²)
Θ = the angle whose tangent is (y / x) .
(6i + 8j) is the [Cartesian] vector that takes you from the origin to (6, 8) .
R = √(6² + 8²) = √(36 + 64) = √100 = 10
Θ = tan⁻¹ (8/6) = 53.13° (rounded)
In polar coordinates, the same point is 10 ∠53.13° .
Answer:
If you were to look for a cut on the palmar surface of a dog's leg then you should look at the back area of the front leg below the carpus.
Explanation:
Answer:
Explanation:
Near the earth's surface where gravity is approximately 10 m/s² downward
v = u + at
v = 5 + (-10)(1) = -5 m/s
so it has the same speed but in the opposite (downward) direction.
Answer:
39)
a) distance traveled = 1 mile
b) displacement = 0 mile
40) - 4 (m/s)
41-) distance traveled = 5 [m]
displacement = 3.6 [m]
Explanation:
The distance differs from the displacement, the distance traveled is equal to the sum of all displacements made by the particle or object.
Displacement is the difference between the initial point and the final point where the object or particle was stopped.
Then we can use the equation given:
The minus sign means the particle is slowing down.
For the 41) we can see the attached image.
In the graph we can see that the particle moves north 3 miles, so that the first distance is 3 miles, then moves 2 miles east being the second distance of 2 miles. Thus the sum of the distances is 3 + 2 = 5 miles.
Displacement is the difference between the endpoint and the initial point since the form of displacement is a straight line, we can use the formula of the straight line or the theorem of Pythagoras.
Answer:
The maximum potential loss is unlimited
Explanation:
<u>The main reason behind this answer is:</u>
The short calls are covered by the long stock position, however the remaining two short calls are naked. so the maximum potential on short naked calls is unlimited.