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aliina [53]
3 years ago
7

Find the range of the function. f(x) = 10-x^2

Mathematics
1 answer:
BARSIC [14]3 years ago
7 0
Answer:
range = x ≤ 10
Step-by-step explanation:
Given in the question the function
f(x)=10-x^2
The range of a function is the complete set of all possible resulting values of the dependent variable F(x) after we have substituted the domain which is the values of x.
domain = set of all integers
range = x ≤ 10
f(x)=10-x²
since any negative value of x will be positive with squared so we will start from 0
f(0) = 10-0² = 10
f(1) = 10 - 1² = 9 = f(-1) = 10 -(-1)²
....and so on.
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Musya8 [376]
Hello!!!!

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Hope this helps!
5 0
3 years ago
PLEASE PLEASEE HELP ITS PAST DUE AND ITS A TEST ILL GIVE BRAINLIEST
agasfer [191]

Answer:

The length will be letter C, 50 m

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3 years ago
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Simplify 4^2 • 4^8
pantera1 [17]

Answer:

4^{10}

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)} , thus

4² × 4^{8} = 4^{(2+8)} = 4^{10}

7 0
3 years ago
6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

or, 0 = - 15

WHICH IS NOT POSSIBLE as 0 ≠ -15

Hence, the given system has NO SOLUTION.

7 0
3 years ago
The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill
lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

A = Height * Base

Where

Height = 10ft --- Height of the pillar

Base = 3ft --- Base of the pillar

So:

A = 10ft * 3ft

A = 30ft^2

The area of the 4 sides of the pillar is:

A_2 = 4 * A --- i.e. 4 multiplied by the area of 1 side

A_2 = 4 * 30ft^2

A_2 = 120ft^2

The area of the 2 pillars is:

Area_1 = 2 * A_2 --- i.e. 2 multiplied by the area if 1

Area_1 = 2 * 120ft^2

Area_1 = 240ft^2

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}

Where:

h = 2 -- the height

l = w = 3 --- the base of the pillar is the length and width of the pyramid.

So, we have:

Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}

Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}

Area = 3\sqrt{5} + 3\sqrt{5}

Area = 6\sqrt{5}

For the two pyramids, the area is:

Area_2 = 2 * 6\sqrt 5 -- 2 multiplied by area of 1

Area_2 = 12\sqrt 5

Area_2 = 26.8

So, the total area to be painted is:

Total = Area_1 + Area_2 --- the sum of the area of the pillars and the pyramids

Total = 240+26.8

Total = 266.8ft^2

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

Cost = 80 * 266.8

Cost = Rs.21344

Read more at:

brainly.com/question/14320476

7 0
3 years ago
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