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3 years ago

Find the range of the function. f(x) = 10-x^2

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

Answer:
range = x ≤ 10
Step-by-step explanation:
Given in the question the function
f(x)=10-x^2
The range of a function is the complete set of all possible resulting values of the dependent variable F(x) after we have substituted the domain which is the values of x.
domain = set of all integers
range = x ≤ 10
f(x)=10-x²
since any negative value of x will be positive with squared so we will start from 0
f(0) = 10-0² = 10
f(1) = 10 - 1² = 9 = f(-1) = 10 -(-1)²
....and so on.

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Answer:

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Step-by-step explanation:

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Since each quarter is worth $0.25, the total value of quarters is given by 0.25x.

And since each dime is worth $0.10, the total value of dimes is given by 0.1(27-x).

We know that the total value of all 27 coins is $5.55. So, we can write the following equation:

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First, let’s multiply everything by 100 to remove the decimals. So:

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Distribute:

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Combine like terms:

$15x+270=555$

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Divide both sides by 15:

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So, the value of x is 19.

This means that there are 19 quarters.

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