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alexandr402 [8]
3 years ago
11

An electric car can go 150 km on a test track at a constant speed of 100 km/hr on one charge of its batteries. The test track is

an oval with no stops or other cars. You can assume that air resistance is the only form of friction. How far can it go on the test track if it moves at a constant speed of 50 km/hr?
Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

75km

Explanation:

First we need to understand for how long the battery can work. We can do that by dividing the total distance traveled by the speed of the race car. Since we do have both measurements required we can find the time. And so we get......

\frac{150km}{100km/hr} = 1.5 hours

Now in order to find distance traveled by an object we need to multiply its speed by the time it traveled. Now since we have both of this measurements  we can fin the traveling distance.  We do ......

\frac{50km}{1hour} x 1.5 hours = 75km

And just like this we get the answer 75km

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A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi
Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A =  \sqrt{\frac{1.25\  \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

6 0
3 years ago
What is the minimum speed needed to fire a champagne cork a distance of 11m?
Crank

To start with solving this problem, let us assume a launch angle of 45 degrees since that gives out the maximum range for given initial speed. Also assuming that it was launched at ground level since no initial height was given. Using g = 9.8 m/s^2, the initial velocity is calculated using the formula:

(v sinθ)^2 = (v0 sinθ)^2 – 2 g d

where v is final velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m

Rearranging to find for v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>

<span>v0 = 10.383 m/s</span>

8 0
4 years ago
A scientist in Northern California is studying the tree rings of a very old redwood tree. He notices that the oldest tree rings
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Answer: colder and drier

Explanation:

Trees don’t grow well in wet climates, nor when they are cold. The wider the rings, the healthier the tree is. Since it was narrow and then wide, was bad climate and then good.

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There is need 4.5 hours to fill the pool in case if both pipes are open

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