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masha68 [24]
3 years ago
12

Indicar cuantas actividades implica: Encerrar con un círculo los verbos conjugados. Copiarlos, en la línea punteada, al lado de

sus sinónimos.
Physics
1 answer:
pochemuha3 years ago
3 0

Answer:

Necesitas poner màs información.

You might be interested in
¿Una persona de 60 corriendo a 4 m/s, tiene más energía cinética que un proyectil de 10 gramos a 300 m/s?
Svet_ta [14]

Explanation:

The question says that "Does a 60 kg person running at 4 m/s have more kinetic energy than a 10 gram projectile at 300 m/s ? "

Speed of a person is 4 m/s

Mass of a person is 60 kg

Kinetic energy of a person is : K=\dfrac{1}{2}mv^2

So,

K=\dfrac{1}{2}\times 60\times 4^2\\\\K=480\ J

Mass of a projectile is 10 grams or 0.01 kg

Speed of a projectile is 300 m/s

Kinetic energy of a projectile is :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 0.01\times (300)^2\\\\K=450\ J

So, it is clear that the kinetic energy of a person is more than that of the kinetic energy of a projectile.

8 0
3 years ago
8)
Pachacha [2.7K]

Answer: The answer would be 10

Explanation:

7 0
3 years ago
A solid cylinder of mass M = 45 kg, radius R = 0.44 m and uniform density is pivoted on a frictionless axle coaxial with its sym
user100 [1]

Answer:

w_f = 1.0345 rad/s

Explanation:

Given:

- The mass of the solid cylinder M = 45 kg

- Radius of the cylinder R = 0.44 m

- The mass of the particle m = 3.6 kg

- The initial speed of cylinder w_i = 0 rad/s

- The initial speed of particle V_pi = 3.3 m/s

- Mass moment of inertia of cylinder I_c = 0.5*M*R^2

- Mass moment of inertia of a particle around an axis I_p = mR^2

Find:

- What is the magnitude of its angular velocity after the collision?

Solution:

- Consider the mass and the cylinder as a system. We will apply the conservation of angular momentum on the system.

                                     L_i = L_f

- Initially, the particle is at edge at a distance R from center of cylinder axis with a velocity V_pi = 3.3 m/s contributing to the initial angular momentum of the system by:

                                    L_(p,i) = m*V_pi*R

                                    L_(p,i) = 3.6*3.3*0.44

                                    L_(p,i) = 5.2272 kgm^2 /s

- While the cylinder was initially stationary w_i = 0:

                                    L_(c,i) = I*w_i

                                    L_(c,i) = 0.5*M*R^2*0

                                    L_(c,i) = 0 kgm^2 /s

The initial momentum of the system is L_i:

                                    L_i = L_(p,i) + L_(c,i)

                                    L_i = 5.2272 + 0

                                    L_i = 5.2272 kg-m^2/s

- After, the particle attaches itself to the cylinder, the mass and its distribution around the axis has been disturbed - requires an equivalent Inertia for the entire one body I_equivalent. The final angular momentum of the particle is as follows:

                                   L_(p,f) = I_p*w_f

- Similarly, for the cylinder:

                                   L_(c,f) = I_c*w_f

- Note, the final angular velocity w_f are same for both particle and cylinder. Every particle on a singular incompressible (rigid) body rotates at the same angular velocity around a fixed axis.

                                  L_f = L_(p,f) + L_(c,f)

                                  L_f = I_p*w_f + I_c*w_f

                                  L_f = w_f*(I_p + I_c)

-Where, I_p + I_c is the new inertia for the entire body = I_equivalent that we discussed above. This could have been determined by the superposition principle as long as the axis of rotations are same for individual bodies or parallel axis theorem would have been applied for dissimilar axes.

                                  L_i = L_f

                                  5.2272 = w_f*(I_p + I_c)

                                  w_f =  5.2272/ R^2*(m + 0.5M)

Plug in values:

                                  w_f =  5.2272/ 0.44^2*(3.6 + 0.5*45)

                                  w_f =  5.2272/ 5.05296

                                  w_f = 1.0345 rad/s

5 0
3 years ago
Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep
nignag [31]

Answer:

\dfrac{r_1}{r_2}=4.123

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them r_1

Final separation between them r_2

Let Q and q be the charges on them then

F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123

6 0
3 years ago
When a fighter pilot feels massive amounts of force when their planes turn quickly applies to_
sattari [20]

Answer:

The answer is A - Newtons First Law

Explanation:

The law is what we call "Inertia". The law basically states that an object wants to stay where it is. We can see the effect from our cars, albeit with less force. When the car turns right, your body goes left, opposite to the turns direction due to us moving position in the car.

3 0
3 years ago
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