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oee [108]
3 years ago
8

The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 8.1% per day. f

ind the half-life of this substance (that is, the time it takes for one-half the original amount in a given sample of this substance to decay).
Chemistry
1 answer:
Elanso [62]3 years ago
5 0
The general equation for radioactive decay is;
N = N₀e^(-λt)
x - decay constant (λ) - rate of decay 
t-  time 
N - amount remaining after t days , since we are calculating the half life, amount of time it takes for the substance to to be half its original value, its N₀/2
N₀ - amount initially present 
substituting the values 
N₀/2 = N₀e^(-0.081t)
0.5 = e^(-0.081t)
ln (0.5) = -0.081t
-0.693 = -0.081t
t = 0.693 / 0.081 
  = 8.55
half life of substance is 8.55 days 
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If 585.24 Joules of heat are added to 53.2 grams of water at 24.15oC, what will the new temp. be?
spayn [35]
E = mct
Energy = (mass) x (specific heat capacity of water) x (change in temp)

585.24 = 53.2 x 4.2 x (X-24.15)


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3 0
3 years ago
Silver (Ag) has two stable isotopes: 107Ag, 106.90 amu, and 109Ag, 108.90 amu. If the average atomic mass of silver is 107.87 am
inysia [295]

Answer:

  • The abundance of 107Ag is 51.5%.
  • The abundance of 109Ag is 48.5%.

Explanation:

The <em>average atomic mass</em> of silver can be expressed as:

107.87 = 106.90 * A1 + 108.90 * A2

Where A1 is the abundance of 107Ag and A2 of 109Ag.

Assuming those two isotopes are the only one stables, we can use the equation:

A1 + A2 = 1.0

So now we have a system of two equations with two unknowns, and what's left is algebra.

First we<u> use the second equation to express A1 in terms of A2</u>:

A1 = 1.0 - A2

We <u>replace A1 in the first equation</u>:

107.87 = 106.90 * A1 + 108.90 * A2

107.87 = 106.90 * (1.0-A2) + 108.90 * A2

107.87 = 106.90 - 106.90*A2 + 108.90*A2

107.87 = 106.90 + 2*A2

2*A2 = 0.97

A2 = 0.485

So the abundance of 109Ag is (0.485*100%) 48.5%.

We <u>use the value of A2 to calculate A1 in the second equation</u>:

A1 + A2 = 1.0

A1 + 0.485 = 1.0

A1 = 0.515

So the abundance of 107Ag is 51.5%.

3 0
3 years ago
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