Answer:
Part 1) m∠1=45°
Part 2) m∠3=45°
Part 3) m∠2=135°
Part 4) m∠4=135°
Step-by-step explanation:
we know that
m∠1=m∠3 -----> by vertical angles Equation A
m∠2=m∠4 -----> by vertical angles Equation B
m∠1+m∠2=180° ----> by supplementary angles (linear pair) Equation C
3(m∠1+m∠3) = m∠2+m∠4 ----> Equation D
Substitute equation A and equation B in equation D
3(m∠1+m∠1) = m∠2+m∠2
6(m∠1) = 2m∠2
3(m∠1) =m∠2 -----> equation E
Substitute equation E in equation C and solve for m∠1
m∠1+3(m∠1)=180°
4(m∠1)=180°
m∠1=45°
<em>Find the measure of m∠3</em>
Remember that
m∠1=m∠3 (equation A)
therefore
m∠3=45°
<em>Find the measure of m∠2</em>
Remember that
m∠2=3(m∠1) (equation E)
substitute the value of m∠1
m∠2=3(45°)=135°
<em>Find the measure of m∠4</em>
Remember that
m∠2=m∠4 (equation B)
therefore
m∠4=135°
Answer:
18
Step-by-step explanation:
Answer:
15 days.
Step-by-step explanation:
46 - 16 = 30.
It falls 2 seconds behind each day so the number of required days
= 30 / 2 = 15.
Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
Answer:
6x-21+5 = -19 Distribute
6x-16 = -19 Combine like terms
6x = -3 Add
x = -1/2 Division
