Answer:
magnitude: 21.6; direction: 33.7 degrees
Explanation:
When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have
vector: (-3,-2)
Scalar: -6
so the vector multiplied by the scalar will have components

The magnitude is given by Pythagorean's theorem:

and the direction is given by the arctan of the ratio between the y-component and the x-component:

Answer:
Explanation:
12.0 kv primary voltage
315 kv secondary voltage ( converted voltage ) V1 or Vo
v2 (Vn)= 730 kv new secondary voltage
a) Ratio of turns in 730 kv to turns in 315 kv
=
therefore the ratio of turns = 2.317 ≈ 2.32
B) ratio of the new current output to the old current output for the same power input to the transformer
since the power input is the same
equation 1
Vp = primary voltage, Vo = old secondary voltage, Vn = new secondary voltage, In = new secondary current, Io = old secondary current
therefore equation 1 becomes
= 315 / 730 = 0.43
Answer:
4987N
Explanation:
Step 1:
Data obtained from the question include:
Mass (m) = 0.140 kg
Initial velocity (U) = 28.9 m/s
Time (t) = 1.85 ms = 1.85x10^-3s
Final velocity (V) = 37.0 m/s
Force (F) =?
Step 2:
Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:
F = m(V + U) /t
F = 0.140(37+ 28.9) /1.85x10^-3
F = 9.226/1.85x10^-3
F = 4987N
Therefore, the magnitude of the horizontal force applied is 4987N
Answer:
Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]
Explanation:
This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.
The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.
We know that the potential energy is defined by:
![E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20where%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
We can clear the mass from this equation:
![m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BE_%7Bp%7D%20%7D%7B%28g%2Ah%29%7D%20%5C%5Cm%3D%5Cfrac%7B250%20%7D%7B%289.81%2A5%29%7D%20%5C%5C%5C%5Cm%3D5.09%5Bkg%5D)
When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.
In such a way that its potential energy would be transformed into kinetic energy.
![E_{k} = E_{p} \\E_{k} =kinetic energy [J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%20E_%7Bp%7D%20%5C%5CE_%7Bk%7D%20%3Dkinetic%20energy%20%5BJ%5D)
Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.