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2 years ago

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are

Physics

1 answer:

STatiana [176]2 years ago

3 0

<h2>Force on the bottom of the container due to liquids is 21.86 N</h2>

Explanation:

Total force is total weight of liquid.

Weight = Mass x Acceleration due to gravity

Liquid 1

Volume = 0.574 L = 574 cm³

Density = 2.50 g/cm³

Mass = 574 x 2.50 = 1435 g = 1.435 kg

Liquid 2

Volume = 0.445 L = 445 cm³

Density = 1.04 g/cm³

Mass = 445 x 1.04 = 462.8 g = 0.463 kg

Liquid 3

Volume = 0.498 L = 498 cm³

Density = 0.659 g/cm³

Mass = 498 x 0.659 = 328.18 g = 0.33 kg

Total mass of liquids = 1.435 + 0.463 + 0.33 = 2.228 kg

Weight = Mass x Acceleration due to gravity

Weight = 2.228 x 9.81

Weight = 2.228 x 9.81 = 21.86 N

Force on the bottom of the container due to these liquids = 21.86 N

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From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of

alexandr1967 [171]

Answer:

The value is $h = 11930 \ m$

Explanation:

From the question we are told that

The temperature is $T = 300 \ K$

Generally the root mean square speed of the oxygen molecules is mathematically represented as

$v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }$

Here R is the gas constant with a value $R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}$

M is the molar mass of oxygen molecule with value $M = 0.032 \ kg /mol$

$\frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h$

=> $h = 11930 \ m$

4 0

2 years ago

A batter hits a pop fly, and the baseball (with a mass of 148 g) reaches an altitude of 265 ft. If we assume that the ball was 3

den301095 [7]

Answer:

The increase in potential energy of the ball is 115.82 J

Explanation:

Conceptual analysis

Potential Energy (U) is the energy of a body located at a certain height (h) above the ground and is calculated as follows:

U = m × g × h

U: Potential Energy in Joules (J)

m: mass in kg

g: acceleration due to gravity in m/s²

h: height in m

Equivalences

1 kg = 1000 g

1 ft = 0.3048 m

1 N = 1 (kg×m)/s²

1 J = N × m

Known data

$h_2 = 265ft * \frac{0.3048m}{ft} = 80.77m$

$h_1 = 3ft * \frac{0.3048m}{ft} = 0.914m$

$m = 148g*\frac{1kg}{1000g} = 0.148kg$

$g = 9.8 \frac{m}{s^2}$

Problem development

ΔU: Potential energy change

ΔU = U₂ - U₁

U₂ - U₁ = mₓgₓh₂ - mₓgₓh₁

U₂ - U₁ = mₓg(h₂ - h₁)

$U_2 - U_1 = 0.148kg * 9.8 \frac{m}{s^2}*(80.77m - 0.914m) = 115.82 N * m = 115.82J$

The increase in potential energy of the ball is 115.82 J

5 0

2 years ago

A ball is dropped from a cliff. determine how far the ball fell after 7.5 seconds

grin007 [14]

Answer:

The ball fell 275.625 meters after 7.5 seconds

Explanation:

If an object is left on free air (no friction), it describes an accelerated motion in the vertical direction, powered exclusively by the acceleration of gravity. The formulas needed to compute the different magnitudes involved are

$V_f=gt$

$\displaystyle y=\frac{gt^2}{2}$

Where $V_f$ is the final speed of the object in free fall, assumed positive downwards, t is the time elapsed since the release and y is the vertical distance traveled by the object

The ball was dropped from a cliff. We need to calculate the vertical distance the ball went down in t=7.5 seconds. We'll use the formula

$\displaystyle y=\frac{gt^2}{2}$

$\displaystyle y=\frac{(9.8)(7.5)^2}{2}$

$Y=275.625\ m$

5 0

3 years ago

_______ are nonmetals that react with metals to form salts.

kari74 [83]

i’m pretty sure it’s , the alkali metals

5 0

2 years ago

A small boat sailed straight north out of a harbor in strong east wind (blowing from west to east). After sailing for 120 minute

Amiraneli [1.4K]

it can be said that the speed of the east wind is

v=0.3608m/s

From the question we are told

A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).

After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,

what is the speed of the east wind?.

<h3> the speed of the east wind</h3>

Generally the equation for the distance is mathematically given as

BA=3000sin60

BA=2598.07m

Therefore

the speed of the east wind

$V_w=\frac{BA}{120*60}\\\\V_w=\frac{2598.07}{120*60}$

v=0.3608

For more information on this visit

brainly.com/question/22568180

7 0

2 years ago