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Over [174]
2 years ago
7

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are

Physics
1 answer:
STatiana [176]2 years ago
3 0
<h2>Force on the bottom of the container due to liquids is 21.86 N</h2>

Explanation:

Total force is total weight of liquid.

Weight = Mass x Acceleration due to gravity

Liquid 1

        Volume = 0.574 L = 574 cm³

        Density = 2.50 g/cm³

        Mass = 574 x 2.50 = 1435 g = 1.435 kg

Liquid 2

        Volume = 0.445 L = 445 cm³

        Density = 1.04 g/cm³

        Mass = 445 x 1.04 = 462.8 g = 0.463 kg

Liquid 3

        Volume = 0.498 L = 498 cm³

        Density = 0.659 g/cm³

        Mass = 498 x 0.659 = 328.18 g = 0.33 kg

Total mass of liquids = 1.435 + 0.463 + 0.33 = 2.228 kg

Weight = Mass x Acceleration due to gravity

Weight = 2.228 x 9.81

Weight = 2.228 x 9.81 = 21.86 N

Force on the bottom of the container due to these liquids = 21.86 N

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Using this formula Vj = V; + at, If a vehicle starts from rest
Furkat [3]

Answer:

<em>The final speed of the vehicle is 36 m/s</em>

Explanation:

<u>Uniform Acceleration</u>

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

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The vehicle starts from rest (vo=0) and accelerates at a=4.5 m/s2 for t=8 seconds. The final speed is:

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2 years ago
4. A box of books weighing 325 N moves at a constant velocity across the floor when the box is pushed with a force of 425 N exer
Rudik [331]

Answer:

0.61°

Explanation:

Since the box move at constant velocity, it means there is no acceleration then we can say it has a balanced force system.

Pulling force= resistance force

From the formula for pulling force,

F(x)= Fcos(θ)

= 425×cos(35.2)

=347N

The force exerted downward at an angle of 35.2° below the horizontal= Fsin(θ)= 425sin(35.2)

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We can now equates the pulling force to resistance force

570 (α)= 347N

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3 years ago
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The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

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As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

a = \frac{v_f -v_0}{t} \\\\

<em>at the highest point on the incline plane, the final velocity </em>v_f<em> is zero</em>

a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

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