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galina1969 [7]
2 years ago
8

F(x) = |x + 2| – 5 reflection over the x-axis

Mathematics
1 answer:
USPshnik [31]2 years ago
3 0

Answer:

y=|x+2|−5 is your answer

Step-by-step explanation:

hope this helps

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A bicycle wheel makes five rotations. the bicycle travels 44.48 ft. Find the diameter of the wheel in inches.
Tema [17]

Answer:

2.42 feet

Step-by-step explanation:

the bicycle wheel rotates 5 times and travels 37.94 feet, then we know that the circumference of the wheel (the outside of the wheel as it touches the ground 5 times around) is 37.94/5 = 7.588

 

Then we use the formula for the circumference of a circle: 2(pi)(radius) = circumference

 

We plug in what we know 2(3.14)(radius) = 7.588 and then solve for the radius

 

We divide 2 from both sides of the equation (3.14)(radius) = 3.794

 

We divide pi from both sides (radius) = 1.208

 

Then the last step, we multiply the radius by 2, because we need the diameter, which is double the radius

 

1.208 * 2 = 2.416 or 2.42 rounded up

 

Final answer = 2.42 feet

7 0
3 years ago
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I’m need help with the question in general.
navik [9.2K]

Answer:

I Cant  See

Step-by-step explanation:

8 0
2 years ago
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Can someone help me please?? in Algblra2 - Variations, Progression, and Theorems
VashaNatasha [74]
If (y-1) is a factor of f(y), f(y)=0 when y=1.  So if you find that f(1)=0, then (y-1) is a factor of f(y).

f(y)=y^3-9y^2+10y+5

f(1)=1-9+10+5=7

Since f(1)=7, (y-1) is not a factor.
5 0
3 years ago
Mel Company has a net income, before taxes, of $95,000. The treasurer of the company estimates 45% of net income will have to be
docker41 [41]
95,000 x .45=$42,750 for both federal and state tax..
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6 0
3 years ago
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(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the
fredd [130]

In terms of its radius r, the volume of the balloon is

V(r)=\dfrac{4\pi}3r^3

The diameter d is twice the radius, so that in terms of its diameters, the balloon's volume is given by

V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3

Differentiate both sides with respect to time t:

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}

The diameter increases at a rate of \frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}. When the diameter is d=50\,\mathrm{cm}, we have

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}

or about 23,562 cc/min (where cc = cubic centimeters)

5 0
3 years ago
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