Answer:x^3+13x^2+3
Step-by-step explanation:
(2x^3+11x^2+5)-(x^3-2x^2+2)
Clearing brackets
2x^3+11x^2+5-x^3+2x^2-2
Collect like terms
2x^3-x^3+11x^2+2x^2+5-2
x^3+13x^2+3
B. 13
12^2 + 5^2 = c^2
169 = c^2
13 = c
please mark as brainliest :D
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
The width would be 1 inch.
Given: L = length = 5W; P = perimeter = 2(L+W) = 12 inches
Required: W = width;
Formula: P=2(L+W)
Solution:
12 in = 2 (L + W)
6 in = L + W
6 in = 5W + W
6 in = 6W
1 in = W
Cross check:
P = 2(L + W)
12 in = 2(5 in + 1 in)
12 in = 2(6 in)
12 in = 12 in
Sum of angles of a triangle = 180°
91 + 10x - 4 + 8x +3 = 180
18x + 90 = 180
18x = 90
x = 5°
