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3 years ago

Two students with masses of 40kg and 32 kg are sitting 22 m apart. What is the gravitational force of attraction between them?

Physics

1 answer:

HACTEHA [7]3 years ago

4 0

I get 1.76 x 10^-10 Newton.

That's 0.000 000 000 176 Newton

Which is about 0.000 000 000 635 ounce of force pulling them together.

That's why we never notice it.

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2 years ago

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4 years ago

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Answer:

560.06714 Nm

Explanation:

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity = 0

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation = $\pi$ (Half rotation)

v = Velocity of bat = 29.8 m/s

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m = Mass of ball = 0.196 kg

R = Radius of swing = 0.984 m

$\omega_f=\dfrac{v}{r}\\\Rightarrow \omega_f=\dfrac{29.8}{0.984}\\\Rightarrow \omega_f=30.28455\ rad/s$

From equation of rotatational motion

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{30.28455^2-0^2}{2\times \pi}\\\Rightarrow \alpha=145.96958\ rad/s^2$

Moment of inertia is given by

$I=\dfrac{1}{3}MR^2+mR^2\\\Rightarrow I=\dfrac{1}{3}11.3\times 0.984^2+0.196\times 0.984^2\\\Rightarrow I=3.83687577\ kgm^2$

Torque is given by

$\tau=I\alpha\\\Rightarrow \tau=3.836875776\times 145.96958\\\Rightarrow \tau=560.06714\ Nm$

The torque the pitcher applies is 560.06714 Nm

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