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cupoosta [38]
3 years ago
6

Pls help me find the electrons of these 4 questions asap.​

Physics
1 answer:
jeka943 years ago
5 0
92,92,5,5.. this is what i found but i’m not sure
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The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this
antoniya [11.8K]

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

3 0
3 years ago
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