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3 years ago

Find three ratios equivalent to the ratio described in each situation.

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

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Ayuda con mates por favor

QveST [7]

Answer:

a) $x = -1$ and $y = 5$ , b) $x = 2$ and $y = -1$ , c) $x = -2$ and $y = 1$ , d) $x = 2$ and $y = -9$ , e) $x = 2$ and $y = -2$ , f) $x = 2$ and $y = -1$ , g) $x = 2$ and $y = -1$ , h) $x = 1$ and $y = 2$ .

Step-by-step explanation:

Each system is solved as follows (Cada sistema es resuelto como sigue):

a) $2\cdot x + y = 3$ and $3\cdot x - y = -8$

$y = 3 - 2\cdot x$

$3\cdot x - 3 + 2\cdot x = -8$

$5\cdot x = -5$

$x = -1$

$y = 5$

b) $x - 2\cdot y = 4$ and $-x+3\cdot y = -5$

$x = 4 + 2\cdot y$

$-4-2\cdot y+3\cdot y = - 5$

$-4+y = -5$

$y = -1$

$x = 2$

c) $-2\cdot x + 5\cdot y = 9$ and $x - y = -3$

$x = y-3$

$-2\cdot y +6 +5\cdot y = 9$

$3\cdot y = 3$

$y = 1$

$x = -2$

d) $5\cdot x - 4\cdot y = 2$ and $3\cdot x + 2\cdot y = -12$

$3\cdot x + 2\cdot y = -12$

$6\cdot x + 4\cdot y = -24$

$4\cdot y = -6\cdot x -24$

$5\cdot x +6\cdot x +24 = 2$

$11\cdot x = -22$

$x = 2$

$y = -9$

e) $x + y = 0$ and $2\cdot x +3\cdot y = -2$

$y = -x$

$2\cdot x -3\cdot x = -2$

$-x = -2$

$x = 2$

$y = -2$

f) $3\cdot x + 5\cdot y = 1$ and $x + y = 1$

$y = 1 - x$

$3\cdot x + 5 - 5\cdot x = 1$

$-2\cdot x = -4$

$x = 2$

$y = -1$

g) $5\cdot x - 2\cdot y = 12$ and $4\cdot x + 3\cdot y = 5$

$x = \frac{12+2\cdot y}{5}$

$x = \frac{5-3\cdot y}{4}$

$\frac{12+2\cdot y}{5} = \frac{5-3\cdot y}{4}$

$4\cdot (12+2\cdot y) = 5\cdot (5-3\cdot y)$

$48 + 8\cdot y = 25 - 15\cdot y$

$23\cdot y = -23$

$y = -1$

$x = 2$

h) $7\cdot x + 8\cdot y = 23$ and $3\cdot x + 2\cdot y = 7$

$3\cdot x + 2\cdot y = 7$

$12\cdot x + 8\cdot y = 28$

$8\cdot y = 28 - 12\cdot x$

$7\cdot x +28-12\cdot x = 23$

$-5\cdot x = -5$

$x = 1$

$y = 2$

8 0

3 years ago

Some help me with this math problem

Anestetic [448]

Only the upper-left statement is NOT true.

5 0

3 years ago

Last year, Mollie collected 64 pieces of candy while trick or treating. This year her costume is so fabulous that people were ex

never [62]

Answer:

79.6875 % If you can round, please do.

Step-by-step explanation:

5 0

2 years ago

If you can solve it.Thanks in advance

vivado [14]

Answer:

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

Step-by-step explanation:

we have

$f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}$

$g(x)=\frac{1}{x^{2}+1}$

we know that

In the function

$f(g(x))$

The variable of the function f is now the function g(x)

substitute

$f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}$

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

4 0

3 years ago

I really need math help.

fenix001 [56]

When you see the 'line' is increasing starting from 0 to 2 hours, this indicates that the person on the graph is riding up a hill. This is known as positive acceleration or constant positive acceleration.

Where you see the 'line' stays the same 2 to 5 hours, this can indicate that the bike rider is doing one or two things. One thing the biker could be doing is taking a rest, and the other could be that the biker is riding at a leveled ground. This could be known as having constant velocity or zero acceleration.

Finally, where the 'line' is decreasing from 5 to 6 hours, this can indicate that biker is riding, possibly, down a hill. This is known as negative acceleration.

And of course, when the 'line' is going up again from 6 to 7 hours, this indicates that the biker is riding up a hill or increasing his speed. This is known as positive acceleration or constant positive acceleration.

•

- Marlon Nunez

4 0

3 years ago