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Sergeu [11.5K]
3 years ago
5

A Rüppell's vulture can eat up to 10 percent of its body weight in meat during a single meal. Consider a 19-pound Rüppell's vult

ure. How many pounds of meat can it consume in a single meal?
A. 1.7 pounds
B. 1.6 pounds
C. 1.9 pounds
D. 1.19 pounds
Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

The answer is C) 1.9

olganol [36]3 years ago
8 0
C 1.9 because 19 times 10 percent is 1.9 so the answer woyld be 1.9
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4. Simplify the following using the quotient rule of exponents:
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Answer:

31=1/1

33=1/1

30=3/10

3-=-3

Step-by-step explanation:

7 0
3 years ago
What is:<br> 13 to the 3rd power<br> 2/5 to the second power<br> And 0.9 to the second power
Anna007 [38]
1. 13*13*13 =2197
2. 2/5*2/5 = 4/25
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4 0
3 years ago
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. The population of a city decreased from 25,000 to 24,000. Find the decrease percentage. at to be paid​
Cerrena [4.2K]

Answer:

4%

Step-by-step explanation:

1000 of 25000 is 4%

8 0
3 years ago
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Mervin has some cartons of milk. He sold 2/5 of milk in the morning. He sold 3/4 of the remainder in the afternoon. 24 more cart
sergejj [24]

2/5 were sold in the morning. This is equal to 40% of the total.  That leaves 60% leftover.

 

3/4 were sold in the afternoon. This is equal to 75% of the 60% leftover or 45% of the total (.6x.75).

 

The difference between the two sales is 24 cartons or 5% (45%-40%). If 5% is equal to 24 then you can cross multiply to see what is the equivalent number of cartons out of 100%.

 

5/100 = 24/x

5x = 24(100)

5x = 2400

x = 480

 

ANSWER: 480 cartons

6 0
3 years ago
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
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