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3 years ago

Weight is the downward pull of on mass. What one word completes the sentence?

Physics

1 answer:

lesantik [10]3 years ago

6 0

The word "gravity" belongs between "of" and "on".

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Bowl of water A bowl full of water is sitting out in a pouring rainstorm. Its surface area is 500 cm2. The rain is coming straig

vova2212 [387]

Answer: 4.9 x 10-3 N

Explanation:

A = 500cm^2 = 5 x 10^-2 m^2

V = 5 m/s

R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec

Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3

For the stationary bowl,

dm/dt =pAv= RA

F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N

Bowl moving upwards to speed u = 2 m/s

dm/dt = pA ( v + u) / v

F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N

5 0

3 years ago

If a rocket transfers 2,500,000 MJ of energy when it takes off, how much work is done?

erastovalidia [21]

Answer:

2,500,000 MJ ( $2.5\cdot 10^6 J$ )

Explanation:

According to the work-energy theorem:

The work done on an object is equal to the amount of energy transferred

In this problem, the energy transferred by the rocket is

$E=2,500,000 MJ=2.5\cdot 10^6 J$

Therefore, the work done must be equal to the energy transferred, therefore:

$W=E=2.5\cdot 10^6 J$

6 0

3 years ago

A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It

tigry1 [53]

Answer:

270 m

Explanation:

We can find the distance travelled by the car by using the following suvat equation:

$s=(\frac{u+v}{2})t$

where

s is the distance travelled

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0

v = 45 m/s

t = 12 s

Substituting into the equation, we find:

$s=(\frac{0+45}{2})(12)=270 m$

8 0

3 years ago

Four spheres with positive and negative charges hang from strings.

Arada [10]

Be because it’s the answer

5 0

3 years ago

El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La

allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

$\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta$

En donde:

$\omega_{f}$ : es la velocidad angular final = 2000 rpm = 209,4 rad/s

$\omega_{0}$ : es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.

Resolviendo la ecuación (1) para α, tenemos:

$\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}$

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.

b) El tiempo transcurrido se puede encontrar como sigue:

$\omega_{f} = \omega_{0} + \alpha t$

Resolviendo para t, tenemos:

$t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s$

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0

3 years ago