3 years ago

Plz help!!!!!!!! will mark as brainliest!!!!!!

Physics

1 answer:

Ilya [14]3 years ago

5 0

My best guess would be letter C for this one

hope this helps

You might be interested in

In a tug of war, side A applies 10N force and side B applies 8N .which side will the rope move

choli [55]

The side B will fall down so that means the rope will move the direction of A

7 0

2 years ago

Factors that affect acceleration due to gravity.<br>

hram777 [196]

Answer

Factors Affecting Acceleration Due to Gravity

(1) Position on the planetary surface, it is higher at the axis (poles),

(2) Mass of the planet, higher with planets of larger masses

(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.

Mark me as Brainlist if this answer is helpful for you

8 0

2 years ago

Read 2 more answers

What wave occurs when you push a spring back and forth

kipiarov [429]

Moving a spring back and forth creates a longitudinal wave

4 0

3 years ago

Misha Larkins [42]

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

$KE = \frac{1}{2}mv^2$

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

$U_s = \frac{1}{2}kx^2$

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

$E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2$

We can simplify and solve for 'x'.

$mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}$

Plug in the givens and solve.

$x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}$

3 0

1 year ago

HELP ASAP!! 15 POINTS!!

aksik [14]

Answer:

Its probably D (the sound energy)

4 0

3 years ago