Plz help!!!!!!!! will mark as brainliest!!!!!!

Describe how sound from radio reaches all parts of them room

Licemer1 [7]

Sound waves travel around the boxed room causing them to bounce of the nearest walls to the end of the room>

3 0

3 years ago

Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur

loris [4]

Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

n₂ =2·V₁/(RT₁)

∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

This can be shown based on the fact that the pressure of the container is due to the collision of the gas molecules on the walls of the container, with a kinetic energy that is dependent on temperature and mass, and since the temperature is constant, then the mass of container B is twice that of A and therefore, the number density of container A is twice that of B.

5 0

3 years ago

An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current

balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

Given;

emf of the battery, V = 16.0 V

current at 0.940 ms = 4.86 mA

after a long time, the current becomes 6.45 mA = maximum current

Part (a) The resistance R of the inductor

$R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms$

Part (b) the inductance L of the inductor

$\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}$

where;

L is the inductance

R is the resistance of the inductor

t is time

$L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H$

Therefore, the inductance is 1.67 H

5 0

3 years ago

Anyone who scuba dives is advised not to fly within the next 24 h because the air mixture for diving can introduce nitrogen into

Katyanochek1 [597]

Answer:

Explanation:

Let pressure at surface of earth be P Pa.

pressure at height of 8.1 km in air can be calculated as follows .

pressure due to column of air of 8.1 km height

= h d g , h is height , d is density of air and g is acceleration due to gravity

= 8.1 x 1000 x .87 x 9.8 = 6.9 x 10⁴ Pa .

pressure at the height of 8.1 km

= P - 6.9 x 10⁴ Pa

Pressure due to column of 16 m in the sea

= h d g

16 x 1000 x 9.8

= 15.68 x 10⁴ Pa .

Pressure at depth of 16m

= P + 15.68 x 10⁴

pressure difference between points at height of 8.1 km and pressure at point 16 m deep

= P + 15.68 x 10⁴ - P + 6.9 x 10⁴ Pa

= 22.58 x 10⁴ Pa .

3 0

3 years ago

a tractor pulls a wagon from rest with a constant force of 700 N eventually giving the wagon a speed of 20 km/h. how much work i

Semenov [28]

Work = Force × distance

We need to calculate distance travelled.

20km/hr = 20,000m / 60min → 333.3m/ min

333.3 × 3.5 min = 1,166.6 meters travelled

Force = 700 N and distance = 1,166.6 m

Work done is 700 N × 1,666.6 = 816,620 Nm

Power output = work /time

Power output is 816, 620 Nm / (3.5 × 60sec) →816, 620 / 210 = 3,888.7

Power output is 3,888.7 Watts.

Power output can also be expressed in joules per second so it is also correct to say work done is 3,888.7 J/s

5 0

3 years ago