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olchik [2.2K]
4 years ago
9

What is the acceleration at the apex of a vertical up and down problem?

Physics
1 answer:
Natalija [7]4 years ago
7 0

Answer:

The correct option is +9.81 m/s²

Explanation:

The acceleration of a vertical (up and down) plane depends on if the object is going up or down. Acceleration due to gravity is 9.81 m/s/s or 9.81 m/s². When an object falls/comes down (vertically) without interference, the acceleration of such an object is same as acceleration due to gravity (+9.81 m/s²). However, when an object is thrown/goes up, the acceleration of such objects goes against the gravity (of earth) hence the acceleration is -9.81 m/s².

At the top/apex of a vertical up and down problem, the object will be pulled back down (because of gravity) and hence, it's acceleration becomes +9.81 m/s² (changing from negative while coming up to positive).

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What causes competition among organisms?
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Answer:

Whats up Bmw,

The organisms is caused when both the organisms or species are harmed, which is limited supply of at least one resource from food or even water used by both can be a factor.

Explanation:

Hope I helped you, and let me know if you need help on anything else :p

8 0
4 years ago
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Why is Pluto now called a dwarf planet
zvonat [6]
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There’s a tendency to define objects based on what they are now, but nothing is constant in the universe. There are some issues with the nomenclature, and a definition today may not apply to the same object tomorrow.
7 0
3 years ago
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Tomas wants to paint his bedroom. He goes to the store and buys two cans of paint.
GuDViN [60]
C an inclined plate
youre welcome
8 0
3 years ago
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suppose you use three different scales to weigh bag of oranges one scale says the bag weighs 2.1 lbs a second says it weighs 2.2
Ber [7]

Answer:

It would be 2.2 if you have to round the five to the one but if your not rounding the number, it'd be 2.1.

Explanation:

4 0
3 years ago
How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, assume
Svetach [21]

Answer:

9.56\cdot 10^{-7} C

Explanation:

A parallel-plate capacitors consist of two parallel plates charged with opposite charge.

Since the distance between the plates (1 cm) is very small compared to the side of the plates (19 cm), we can consider these two plates as two infinite sheets of charge.

The electric field between two infinite sheets with opposite charge is:

E=\frac{\sigma}{\epsilon_0}

where

\sigma=\frac{Q}{A} is the surface charge density, where

Q is the charge on the plate

A is the area of the plate

\epsilon_0 = 8.85\cdot 10^{-12}F/m is the vacuum permittivity

In this problem:

- The side of one plate is

L = 19 cm = 0.19 m

So the area is

A=L^2=(0.19)^2=0.036m^2

Here we want to find the maximum charge that can be stored on the plates such that the value of the electric field does not overcome:

E=3\cdot 10^6 N/C

Substituting this value into the previous formula and re-arranging it for Q, we find the charge:

E=\frac{Q}{A\epsilon_0}\\Q=EA\epsilon_0 = (3\cdot 10^6)(0.036)(8.85\cdot 10^{-12})=9.56\cdot 10^{-7} C

7 0
4 years ago
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