Answer:
a. Propanol
b. Propanone
c. Butanal
Explanation:
From the given information:
We are to state which of the given samples are more soluble in water.
The solubility of an organic molecule in water depends on the polarity of the given organic molecule. This solubility behaviour conforms with the general rule -"like dissolve like". Solubility is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature. Water is a polar solvent; therefore, an organic molecule that will also dissolve in water must be polar.
From the first pair, we have propane and propanol.
Propanol is more soluble in water than propane due to its polarity in water.
From the second pair:
Propanone is an alkanone (ketone group) with three carbon chain directly bonded to an oxygen double bond. At the same time, 3-hexanone has six carbon chain ketone group with the oxygen double bond located at the third carbon chain ( a hydrophobic "water-fearing" compound). Thus, the shorter the carbon chain, the more polar the organic molecule is and the more it is likely going to dissolve in water. Therefore, Propanone is more soluble in water than 3-hexanone.
From the third pair: The shorter the carbon chain, the more soluble in water it will become.
Butanal is the fourth element on the alkanal family group while hexanal is the sixth compound in the alkanal family group. As such, butanal is more soluble in water than hexanal.
Be, B, C, N (going from smallest to biggest)
Answer:
A compressed gas cylinder is filled with 5270 g of argon gas.
The pressure inside the cylinder is 2050 psi at a temperature of 18C.
The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.
How many grams of argon remains in the cylinder?
Explanation:
First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:
Mass of Ar gas is --- 5270g.
The number of moles of Ar gas:

Temperature T=(18+273)K=291K
Pressure P=2050psi

Volume V=?

Using this volume V=22.6L
Pressure=650psi=44.2atm
Temperature T= (26+273)K=299K
calculate number of moles "n" value:

Mass of 40.7mol of Ar gas:

Answer:
The mass of Ar gas becomes 1625.8g.
Lithium i believe is the answer
This problem is providing the chemical reaction whereby barium nitride reacts with water to produce barium hydroxide and ammonia, so the number of moles of barium nitride are required in order to produce 8.3 moles of ammonia. It asks for us to evaluate the student's setup, so we conclude the answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3", according to:
<h3>Mole ratios:</h3>
In chemistry, stoichiometric calculations are used to figure out the moles or mass of a substance, given information about another one in the reaction. In this case, for the given chemical equation:

We evidence a 1:2 mole ratio of barium nitride to ammonia, for that reason, the student's setup:

Is incorrect, because the ammonia must be accompanied by a 2 rather than the 1 it is given there:

Thereby, the correct answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3"
Learn more about mole ratios: brainly.com/question/15288923