Answer:
182.3 g
Explanation:
number of mols of HCl = 5 mols
molecular weight of HCl = 36.46 g/mol
m = mass of HCl = number of mols x molecular weight
m = 5 mols * 36.46 g/mol
m = 182.3 g
Answer:
Explanation:
In sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen .
In sulfur trioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen.
The ratio of oxygen which reacts with 32.06 gram of sulfur is 32: 48 .
This ratio is equal to 2 : 3.
This is in accordance with law of multiple proportion because , the ratio of mass of oxygen which reacts with constant mass of sulfur is integral ratio . Hence they are in accordance with law of multiple proportions.
Answer:
4
Explanation:
in (C2H2O2)2 there are 4 hydrogen atoms
<span>1) </span><span>Deduce
the two masses and see the amount of water was driven off when heated: </span><span>
<span>5.03 g -
4.23 g = 0.8 g H2O given off </span>
<span>2) Change
mass from grams to moles of H2O: </span>
<span>0.8 g H2O
/ 18 g H2O in 1 mole = 0.044 mol H2O </span>
<span>3) Change
left over mass to moles of BaCl2 .</span></span>
<span>
<span>4.23 g
BaCl2 / 207 g BaCl2 in 1 mol = 0.021 mol BaCl2 </span>
<span>4)Find
the ratio of mol H2O to mol BaCl2: </span>
<span>0.044 mol
H2O : 0.021 mol BaCl2 </span>
<span>5) The
resulting ratio is 2:1 so two H2O for each BaCl2, thus, the hydrate was named: </span>
<span>Barium
chloride di-hydrate</span></span>
A product...............................................................
