Boyle found that when the pressure of gas at a constant temperature is increased, the volume of the gas decreases. when the pressure of gas is decreased, the volume increases. this relationship between pressure and volume is called Boyle's law.
There are two naturally occurring isotopes of gallium: mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:
%Ga-71=100-60.11=39.89%
Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.
Thus, in this case:
Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)
From the periodic table, atomic mass of Ga is 69.723 amu.
Putting the values,

Thus,

Rearranging,

Therefore, mass of Ga-71 isotope is 70.9246 amu.
Answer:
the answer is the swecond option
Explanation:
Its b ur well come
Answer:
a. True
b. True
c. False
d. True
Explanation:
a). A a very low substrate concentration ,
. Thus according to the Machaelis-Menten equation becomes
![$V_0 = \frac{V_{max} \times [S]}{Km}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%7D%24)
Here since the
varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.
b). The Michaelis -Menten kinetics equation states that :
![$V_0 = \frac{V_{max} \times [S]}{Km+[S]}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%2B%5BS%5D%7D%24)
Here the initial velocity changes directly with the substrate concentration as
is directly proportional to [S]. But
is same for any particular concentration of the enzymes. Thus, option (b) is true.
c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.
d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.
Answer:
http://hyperphysics.phy-astr.gsu.edu/hbase/Biology/imgbio/treecycle.p ng
Explanation: