Answer: To solve for the net magnetic field of two circular loops of wire, each containing a single turn
B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]
Where B net = Net magnetic field
B net = √2 × (NUI/ 2R)
B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034
B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068
B net = 4.72 × 10^-5 T
A year on Earth is 365 and 1/4 days (rounded). It corresponds to
one revolution of the Earth in our orbital path around the sun.
Since the mass is 5 grams the acceleration is: 4000 m/s^2
But if the mass is 5 Kilograms the acceleration is: 4 m/s^2
Answer:
AAT-CAG-GT
AAT-CGA-GT
Explanation:
Because they are both missing one letter
ANOTHER RUNNING DOG
Explanation:
In the given question it is to find a suitable reference point to describe the motion of dog. Here I could suggest that it is better to compare the dog with another running dog to create the relative speed difference to get a reliable motion variation.
Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to another dog which is already in motion.
Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with another dog running.
