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My name is Ann [436]
3 years ago
5

Incentives influence people's economic decisions by:

Physics
2 answers:
Serggg [28]3 years ago
7 0

Answer:

making it easier to perform a cost-benefit analysis of a decision.reducing the marginal benefits for a particular choice.

Explanation:

brilliants [131]3 years ago
6 0

Answer: Making certain choices more beneficial than others.

Explanation: Just took test - Apx

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Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
stiv31 [10]

Answer:

300 Newtons

Explanation:

Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.

The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have

Force = 12 × 25 = 300 Newtons or 300 N for short.

3 0
3 years ago
What is the difference between each distance traveled and displacement travled
-BARSIC- [3]

Displacement is a vector magnitude that depends on the position of the body which is individualistic for the trajectory.

While, Distance is a scalar magnitude that measures over the trajectory.

8 0
3 years ago
What two measurements are needed to determine density?
g100num [7]
Density is defined as (mass) per unit (volume).  So in order to calculate
the density of a glob of some substance, you pretty much have to measure
its mass and its volume. 
7 0
3 years ago
Read 2 more answers
Which of two factors influence the weight of an object due to gravitational pull?
Maslowich
Where are the factors ... to this question

5 0
4 years ago
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
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