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den301095 [7]
3 years ago
5

Compute the velocity of an object orbiting at height 2Re above the surface of earth

Physics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

The orbital speed can be found using v = SQRT(G*M/R). The R value (radius of orbit) is the earth's radius plus the height above the earth - in this case, 6.59 x 106 m.

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Within a vacuum, the property to all electromagnetic waves is their
bezimeni [28]
The answer is D) Velocity
7 0
3 years ago
the pressure of gas in a cylinder is 70 kilopascals. if the volume of the cylinder is reduced from 8.0 liters to 4.0 liters, wha
Olegator [25]
By Boyle's law:

P₁V₁ = P₂V₂

70*8 = P<span>₂*4

</span>P<span>₂*4 = 70*8
</span>
P<span>₂ = 70*8/4 = 140
</span>
P<span>₂ = 140 kiloPascals.</span>
3 0
3 years ago
Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object
barxatty [35]

Hello!

Recall the equation for gravitational force:
F_g = \frac{Gm_1m_2}{r^2}

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
F_g = 100N

If we were to double one mass and triple another, according to the equation:
F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g

Thus:
6 * F_g = 6 * 100 = \boxed{600N}

5 0
2 years ago
Taden has found a table of the atmospheric layers of the Sun. However, he can’t make out the names of the layers in the chart.
zhenek [66]

The sun is a ball of hot gases containing different kinds of elements at different cores. It has a very high temperature that radiates all throughout the Milky Way galaxy. The sun has three main parts; photosphere, chromospheres and corona. The outer core of a star located at the chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then carbon, oxygen, neon, magnesium silicon and the inert gas. The photosphere is scattered by the loose electrons in the corona’s plasma.

7 0
3 years ago
Read 2 more answers
Question 9 of 27
Ksju [112]

The power of man performing 500 J of work in 8 seconds is 62.5 J/s.

Power can be defined as the pace at which work is completed in a given amount of time.

Horsepower is sometimes used to describe the power of motor vehicles and other machinery.

The pace at which work is done on an item is defined as its power. Power is a temporal quantity.

Which is connected to how quickly a project is completed.

The power formula is shown below.

Power = Energy / Time

Power = E / T

Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.

Here we have given Energy as 500 J and Time as 8 second.

Power = Energy / Time

Power = 500 / 8  Joule / sec

Power = 250 / 4  Joule / sec

Power = 125 / 2 Joule / sec

Power = 62.5 Joule / sec  or  62.5 watt

Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.

So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.

Learn more about Power here:

brainly.com/question/1634438

#SPJ10

6 0
2 years ago
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