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den301095 [7]
3 years ago
5

Compute the velocity of an object orbiting at height 2Re above the surface of earth

Physics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

The orbital speed can be found using v = SQRT(G*M/R). The R value (radius of orbit) is the earth's radius plus the height above the earth - in this case, 6.59 x 106 m.

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A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.
Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
GarryVolchara [31]

I'm in physics, but I think the answer is 22. The angle of reflection is reflecting whatever the angle was so, in this case, it must be 22

3 0
2 years ago
Read 2 more answers
Describe how the composition of gases changes as you travel up through Earth's atmosphere.
Ghella [55]
<span>As the gases go higher in the atmosphere they start to compose or join together</span>
7 0
3 years ago
A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of t
jonny [76]

Answer:

<h2>3</h2>

Explanation:

Using the efficiency formula. Efficiency = MA/VR * 100%

MA = Mechanical Advantage

VR = velocity ratio = \frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}

Distance moved by effort = 4.5m

distance moved by load = 1.5m

VR = 4.5/1.5 =3

Assuming efficiency is 100% (since friction can be ignored)

100% = MA/3 * 100%

1 = MA/3

MA = 3*1

MA = 3

Mechanical Advantage of the ramp is 3

8 0
3 years ago
Question 1: Bicycle pump
belka [17]

Answer: The pressure  of the air when compressed is 5.0\times 10^5Pa

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = 1.0\times 10^5Pa

P_2 = final pressure of gas  =?

V_1 = initial volume of gas  = V

V_2 = final volume of gas  = \frac{V}{5}

1.0\times 10^5\times V=P_2\times \frac{V}{5}  

P_2=5.0\times 10^5Pa

Therefore, the pressure  of the air when compressed is 5.0\times 10^5Pa

4 0
3 years ago
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