Answer: 99.51%
Step-by-step explanation:
Given : A survey found that women's heights are normally distributed.
Population mean : 
Standard deviation: 
Minimum height = 4ft. 9 in.=
Maximum height = 6ft. 2 in.=
Let x be the random variable that represent the women's height.
z-score : 
For x=57, we have
For x=74, we have
Now, by using the standard normal distribution table, we have
The probability of women meeting the height requirement :-
Hence, the percentage of women meeting the height requirement = 99.51%
Answer:
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Step-by-step explanation:
Answer:
- arc second of longitude: 75.322 ft
- arc second of latitude: 101.355 ft
Explanation:
The circumference of the earth at the given radius is ...
2π(20,906,000 ft) ≈ 131,356,272 ft
If that circumference represents 360°, as it does for latitude, then we can find the length of an arc-second by dividing by the number of arc-seconds in 360°. That number is ...
(360°/circle)×(60 min/°)×(60 sec/min) = 1,296,000 sec/circle
Then one arc-second is
(131,356,272 ft/circle)/(1,296,000 sec/circle) = 101.355 ft/arc-second
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Each degree of latitude has the same spacing as every other degree of latitude everywhere. So, this distance is the length of one arc-second of latitude: 101.355 ft.
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<em>Comment on these distance measures</em>
We consider the Earth to have a spherical shape for this problem. It is worth noting that the measure of one degree of latitude is almost exactly 1 nautical mile--an easy relationship to remember.
Answer: 2700
Step-by-step explanation:
