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Liula [17]
3 years ago
14

DUE RIGHT NOW IT WOULD BE NICE IF YOU EXPLAIN TO

Physics
2 answers:
lozanna [386]3 years ago
5 0

Answer: 0-3 minutes

Explanation:

On the side of the graph, it shows you the distance the car was moving. As you know, MPH (miles per hour) shows how fast an object is moving, meaning that the car was going around 0-1 mph around minutes 0-3. Just make sure you know how to read a graph and this will become an easy question for you :)

Talja [164]3 years ago
4 0

Answer:

5-8 minutes the car isn't traveling. The g above is wrong

Explanation:

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Two heavy objects of masses 1 kg and 2 kg are moving towards each other under
SOVA2 [1]

The acceleration of the body in terms of the gravitational constant G is G.

According to Newton's law of universal gravitation;

F = Gm1m2/r^2

G = gravitational constant

m1 = mass of the first body

m2 = mass of the second body

r = distance between the two bodies

Substituting values to find the force on the two bodies;

F = G × 1  × 2/1^2

F = 2G

For the 2 Kg mass

F = ma

m = mass

a = acceleration

F = gravitational force

Hence,

2G = 2a

a = 2G/2

a = G

Learn more: brainly.com/question/13860566

5 0
3 years ago
How much negative charge has been removed from a positively charged electroscope if it has a charge of 7.5×10^-11
vova2212 [387]

I think 4.69 x 108 charges have been removed

5 0
3 years ago
A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?
Dmitriy789 [7]

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

6 0
3 years ago
The conductors that carry the current to electrical devices and ? equipment are the heart of all electrical systems. There are a
MariettaO [177]

Answer:

utilization / effects

Explanation:

Utilization equipment are those equipment that makes use of electric energy for the purpose of chemical, electronic, lighting, heating, electro-mechanical or other alike purposes. Hence utilization best suits the first question mark in the question. Secondly, there are associated effects when current flows through a conductor, not responses.

5 0
3 years ago
PLEASE HELP!!!!!!!!!!!
Alexxandr [17]
I am 100% sure its A.
5 0
3 years ago
Read 2 more answers
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