The acceleration of the body in terms of the gravitational constant G is G.
According to Newton's law of universal gravitation;
F = Gm1m2/r^2
G = gravitational constant
m1 = mass of the first body
m2 = mass of the second body
r = distance between the two bodies
Substituting values to find the force on the two bodies;
F = G × 1 × 2/1^2
F = 2G
For the 2 Kg mass
F = ma
m = mass
a = acceleration
F = gravitational force
Hence,
2G = 2a
a = 2G/2
a = G
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I think 4.69 x 108 charges have been removed
Answer:
592000 J
Explanation:
We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:
1 Pa = 1 Kg/ms²
Therefore,
3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²
Next, we shall determine the workdone.
Workdone is given by the following equation:
Workdone (Wd) = pressure (P) × change in volume (ΔV)
Wd = PΔV
With the above formula, the work done can be obtained as follow:
Pressure (P) = 3.7×10⁵ Kg/ms²
Change in volume (ΔV) = 1.6 m³
Workdone (Wd) =?
Wd = PΔV
Wd = 3.7×10⁵ × 1.6
Wd = 592000 Kgm²/s²
Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:
1 Kgm²/s² = 1 J
Therefore,
592000 Kgm²/s² = 592000 J
Therefore, the Workdone is 592000 J.
Answer:
utilization / effects
Explanation:
Utilization equipment are those equipment that makes use of electric energy for the purpose of chemical, electronic, lighting, heating, electro-mechanical or other alike purposes. Hence utilization best suits the first question mark in the question. Secondly, there are associated effects when current flows through a conductor, not responses.