Answer:
P-value of the test statistic is 2.499
Explanation:
given data:
size sample is 24
sample mean is 414 gm
standard deviation is 15
Null hypotheis is
level of significance is 0.01
from test statics
degree od freedom is = n -1
df = 24 -1 = 13
t = -1.959
from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499
Answer:
0.045 J
Explanation:
The work done on a charge moving through a potential difference is given by
where
W is the work done
q is the charge
is the potential difference
In this problem, we have
q = 0.0050 C is the charge
is the potential difference
Using the formula, we find the work done:
Answer:
Explanation:
Given
Horizontal bar rises with 300 mm/s
Let us take the horizontal component of P be
where is angle made by horizontal bar with x axis
Velocity at y=150 mm
thus
position of
Velocity at this instant