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adell [148]
3 years ago
12

Two heavy objects of masses 1 kg and 2 kg are moving towards each other under

Physics
1 answer:
SOVA2 [1]3 years ago
5 0

The acceleration of the body in terms of the gravitational constant G is G.

According to Newton's law of universal gravitation;

F = Gm1m2/r^2

G = gravitational constant

m1 = mass of the first body

m2 = mass of the second body

r = distance between the two bodies

Substituting values to find the force on the two bodies;

F = G × 1  × 2/1^2

F = 2G

For the 2 Kg mass

F = ma

m = mass

a = acceleration

F = gravitational force

Hence,

2G = 2a

a = 2G/2

a = G

Learn more: brainly.com/question/13860566

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What is happens when a beam of light is traveling through air and is reflected by a glass surface?
DaniilM [7]

When a beam of light is traveling through air and is reflected by a glass surface, then the 2R / (1+R) is the total reflectance through a glass window.

To find the answer, we have to know about reflection.

<h3>What is reflection by glass surface?</h3>
  • Depending on the angle of incidence, the refractive indices of the glass and the light's source, some light is reflected when it strikes a glass surface (e.g., air).
  • The Fresnel equations can be used to calculate the percentage of transmitted and reflected light.
  • Both the front and the rear of glass reflect the light that is traveling through it. In fact, the light may mirror itself several times. Therefore, 2R / (1+R) is the total reflectance through a glass window.
  • These equations predict that ordinary soda-lime window glass will reflect around 8% of the light, assuming a perpendicular incidence angle and no absorption or scattering.

Thus, we can conclude that, when a beam of light is traveling through air and is reflected by a glass surface, then the 2R / (1+R) is the total reflectance through a glass window.

Learn more about the reflection here:

brainly.com/question/5012638

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Math Practice: Cart A loaded with blocks (600g) moving left at 0.7m/s hits stationary cart B (200g).
Vika [28.1K]

Answer:

The velocity of cart B after the collision is 1.29 m/s.

Explanation:

We can find the velocity of cart B by conservation of linear momentum:

p_{i} = p_{f}

m_{A}v_{A_{i}} + m_{B}v_{B_{i}} = m_{A}v_{A_{f}} + m_{B}v_{B_{f}}

Where:

m_{A} is the mass of cart A = 600 g = 0.6 kg            

m_{B} is the mass of cart B = 200 g = 0.2 kg

v_{A_{i}} is the inital velocity of cart A = 0.7 m/s

v_{A_{f}} is the final velocity of cart A = 0.27 m/s

v_{B_{i}} is the initial velocity of cart B = 0

v_{B_{f}} is the final velocity of cart B =?

Taking the left direction as the positive horizontal direction:

0.6 kg*0.7 m/s + 0 = 0.6 kg*0.27 m/s + 0.2 kg*v_{B_{f}}

v_{B_{f}} = 1.29 m/s

                       

Therefore, the velocity of cart B after the collision is 1.29 m/s.

I hope it helps you!  

5 0
3 years ago
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