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3 years ago

Area of square tile, math question

Mathematics

1 answer:

Inessa05 [86]3 years ago

5 0

Answer:

Answer: √49

___________

√49 = 7

Step-by-step explanation:

The area of a square is equal to the square of its side or the product of its side and its side.

A = s², because the sides of a square are congruent.

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Find the area of the figure.

Studentka2010 [4]

Answer:

SOLVE FOR RECTANGLE

Area: lw (length times width)

rectangle: lw (6x6)

AREA=36in

SOLVE FOR TRIANGLE B

Area: A=hbxb/2

A=hb/b2=6·6/2=18

TRIANGLE B=18in

SOLVE FOR TRIANGLE A

Area: A=hbxb/2

The height looks half the height as the other triangle

A=hb/b2=3·4/2=6

TRIANGLE A=6in

{ADD}

36+18+6

TOTAL: 60in

Step-by-step explanation:

HOPE THAT HELPED!!!

3 0

3 years ago

In desperate need. for answer 11 and 12.

Thepotemich [5.8K]

11. The answer would be 3:30 because in all it took her 3:50 minutes so subtract from 7:20 you get 3:30

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2 years ago

Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.

sp2606 [1]

$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}$

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3 years ago

A basket contains apples and oranges. some are ripe and some are not. 30% of the fruits are apples and 50% of the fruits are rip

Lynna [10]

Since 50% are ripe, and you know that 25% are ripe apples, you also can assume 5% of apples aren’t ripe. From that you know that 50% + 5% is ripe oranges, and apples. So 45% are not ripe oranges

8 0

3 years ago

Find the x-coordinate of the vertex of the graph of the equation y=-3x^2+6x+2

Ivanshal [37]

Consider, pls, this solution:
according to the equation y= -3x²+6x+2, where a=-3, b=6 and c=2, and the rule x₀= -b/(2a):
<u>x₀=</u>-6/(-6)<u>=1</u>.
For more info see the attached graph.

4 0

3 years ago