Question

20 mL of a gas at 200K is heated until the new volume is 55 mL. What is the final temperature of the gas?

Answer 1

Answer:

550 K

Explanation:

Given the following data;

Original Volume, V1 = 20mL

Original Temperature, T1 = 200K

New Temperature, V2 = 55mL

To find new temperature T2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

$VT = K$

$\frac{V1}{T1} = \frac{V2}{T2}$

Making T2 the subject of formula, we have;

$T_{2} = \frac{V2}{V1} * T_{1}$

Substituting into the equation;

$T_{2} = \frac{55}{20} * 200\\T_{2} = \frac{11000}{20}\\T_{2} = 550K$

Therefore, the new temperature is 550K.