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alexandr1967 [171]
3 years ago
11

Powdered aluminum is used in the thermite reaction for welding metals. what role does the powdered aluminum play in this reactio

n?
Chemistry
1 answer:
BigorU [14]3 years ago
5 0
Powdered aluminum serves the reducing agent for this reaction. Aluminum powder is known as a powerful reducing agent. <span>Iron(iii) ions would have greater electron affinity as compared to a metallic aluminum thus it would easily gain electrons from aluminum making it less positive in this case formed into a neutral atom. </span><span>The chemical reaction is </span>

<span>Fe2O3 + 2Al = Al2O3 + 2Fe. 
</span>
<span>Oxygen in the oxide compound does not participate in this redox reaction, as it is not changed </span>chemically<span>. Fe2O3 is an ionic compound which has of Fe[3+] ions and O[2-] ions. So, the net ionic reaction would be</span>

<span>Fe3+ + Al + 3O2- = Al3+ + Fe + 3O2- </span>

<span>The ionization energy of aluminum is greater than that of iron, so the said reaction would generate large amount of heat which is needed in welding.</span>
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At normal blood pH pH (7.4), hemoglobin is 80 80 % saturated at a partial pressure of oxygen ( O 2 O2 ) of 40 mmHg 40 mmHg . Use
schepotkina [342]

Answer:

An example of oxygen–hemoglobin (O2–Hb) dissociation curves from (A) one penguin at pH 7.5, 7.4 and 7.3, and (B) the emperor penguin, the bar-headed goose (Anser indicus) (Black and Tenney, 1980) and the domestic duck (Anas platyrhynchos, forma domestica) (Hudson and Jones, 1986) at pH 7.4. Note that as for the bar-headed goose, the O2–Hb dissociation curve of the emperor penguin is significantly left-shifted as compared with the domestic duck (and most birds). The bar-headed goose photo is courtesy of Graham Scott; the domestic duck photo is by Maren Winter (licensed under the terms of the GNU Free Documentation License, Version 1.2 or any later version); the penguin photo is by J.M.

Explanation:

The resulting regression equations from the plots of log[SO2/(100–SO2)] vs log(PO2) (all saturation points, all penguins combined) were:

pH 7.5: log[SO2/(100–SO2)] = 2.92589 × log(PO2) – 4.24338 (N=43, r2=0.98, P<0.0001),

pH 7.4: log[SO2/(100–SO2)] = 2.94767 × log(PO2) – 4.39858 (N=70, r2=0.98, P<0.0001),

pH 7.3: log[SO2/(100–SO2)] = 3.04945 × log(PO2) – 4.72019 (N=38, r2=0.99, P<0.0001),

pH 7.2: log[SO2/(100–SO2)] = 3.15958 × log(PO2) – 4.97618 (N=9, r2=0.99, P<0.0001).

5 0
4 years ago
Atom X contains nine protons and seven neutrons. Atom Z contains nine protons and eight neutrons. Which of the following stateme
MrRissso [65]
I thinks the it is question A.
5 0
3 years ago
CHEMISTRY PLEASE HELP ITS MY FINAL
Elena L [17]

Answer:

1. Periodic Table

2. Periods

3. Groups

4. Metals

5. Non - Metals

6. Metalloids

7. Alkaline Metals

8. Transition Metals

Explanation:

i hope this was right. Tell me if it was wrong.

3 0
3 years ago
Read 2 more answers
Calculate the Lattice Energy of KCl(s) given the following data using the Born-Haber cycle: ΔHsublimation K = 79.2 kJ/mol IE1 K
DanielleElmas [232]

Answer:

Explanation:

  The following equation relates to Born-Haber cycle

\triangle H_f = S + \frac{1}{2} B + IE_M - EA_X+ U_L

Where

\triangle H_f is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

IE_M is ionisation enthalpy of metal

EA_X is electron affinity of non metal atom

U_L is lattice energy

Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

U_L = - 707 KJ / mol

3 0
3 years ago
Its not d.. Don’t Guess
Mariulka [41]
The answer is c I think because u already did this
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