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alexandr1967 [171]
3 years ago
11

Powdered aluminum is used in the thermite reaction for welding metals. what role does the powdered aluminum play in this reactio

n?
Chemistry
1 answer:
BigorU [14]3 years ago
5 0
Powdered aluminum serves the reducing agent for this reaction. Aluminum powder is known as a powerful reducing agent. <span>Iron(iii) ions would have greater electron affinity as compared to a metallic aluminum thus it would easily gain electrons from aluminum making it less positive in this case formed into a neutral atom. </span><span>The chemical reaction is </span>

<span>Fe2O3 + 2Al = Al2O3 + 2Fe. 
</span>
<span>Oxygen in the oxide compound does not participate in this redox reaction, as it is not changed </span>chemically<span>. Fe2O3 is an ionic compound which has of Fe[3+] ions and O[2-] ions. So, the net ionic reaction would be</span>

<span>Fe3+ + Al + 3O2- = Al3+ + Fe + 3O2- </span>

<span>The ionization energy of aluminum is greater than that of iron, so the said reaction would generate large amount of heat which is needed in welding.</span>
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During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.
Travka [436]

<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL

Putting values in above equation, we get:

1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

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3 years ago
Lithium sulphate is used in some medicines and its presence in a medicine can be shown by two a combination of two tests a)expla
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Answer:

A flame test could help by seeing what things it could catch on fire from or the things that could happen with acids etc. I would test the medicine by asking someone who has had it in their life, asking doctors or I would maybe use it myself maybe. (I don’t know about c, sooo sorry)

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