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alexandr1967 [171]
3 years ago
11

Powdered aluminum is used in the thermite reaction for welding metals. what role does the powdered aluminum play in this reactio

n?
Chemistry
1 answer:
BigorU [14]3 years ago
5 0
Powdered aluminum serves the reducing agent for this reaction. Aluminum powder is known as a powerful reducing agent. <span>Iron(iii) ions would have greater electron affinity as compared to a metallic aluminum thus it would easily gain electrons from aluminum making it less positive in this case formed into a neutral atom. </span><span>The chemical reaction is </span>

<span>Fe2O3 + 2Al = Al2O3 + 2Fe. 
</span>
<span>Oxygen in the oxide compound does not participate in this redox reaction, as it is not changed </span>chemically<span>. Fe2O3 is an ionic compound which has of Fe[3+] ions and O[2-] ions. So, the net ionic reaction would be</span>

<span>Fe3+ + Al + 3O2- = Al3+ + Fe + 3O2- </span>

<span>The ionization energy of aluminum is greater than that of iron, so the said reaction would generate large amount of heat which is needed in welding.</span>
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Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
2 years ago
The unit cell of amazonite is made of three pairs of faces, each pair different from the others. The faces are oriented at angle
scZoUnD [109]
<span>The unit cell of amazonite is made of three pairs of faces, each pair different from the others. The faces are oriented at angles to one another that are not 90 degrees. The type of crystal this is is triclinic.
Triclinic crystal system is one of the seven crystal systems, with three basis vectors. </span>
5 0
2 years ago
How many atoms are in 1.204x10^22 moles of arsenic?
ra1l [238]

Answer:

<h2>0.02 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

n =  \frac{1.204 \times  {10}^{22} }{6.02 \times  {10}^{23} }    \\  = 0.02

We have the final answer as

<h3>0.02 moles</h3>

Hope this helps you

7 0
2 years ago
How many formula units make up 36.0 g of magnesium chloride (MgCl2)?
zalisa [80]

Answer: There are 2.29\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles

1 mole of MgCl_2 contains = 6.023\times 10^{23} formula units

Thus 0.38 moles of MgCl_2 contains = \frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23} formula units

Thus there are 2.29\times 10^{23} formula units

6 0
3 years ago
50 Points: What is the mass of 6.12 moles of arsenic (As)?
ozzi

The mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass. That is;

Mass of Arsenic = no. of moles of As × molar mass of As.

According to this question, 6.12 moles of arsenic was given and its molar mass is 74.92g/mol.

Mass of As = 6.12 mol × 74.92g/mol

Mass of As = 459g

Therefore, the mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

Learn more about mass calculations at: brainly.com/question/8101390

4 0
2 years ago
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