Answer: B) Particles can be filtered from a suspension.
Explanation: Colloids are solutions with particle size intermediate between true solutions and suspensions. They exhibit tyndall effect that is scattering of light.
Suspensions have large sized particles which settle when left undisturbed for sometime and thus can be filtered off easily.
The particle size in colloids is less and hence they do not settle under the effect of gravity.
A solution can be homogeneous in which the composition is uniform or heterogeneous in which is the composition is not uniform.
<h3><u>Answer;</u></h3>
= 20,280.25 g or 20.28 Kg
<h3><u>Explanation;</u></h3>
Number of moles, n = Molarity × Volume
Molarity = 6.81 M
Volume = 8.7 L
Number of moles = 6.81 × 8.7
= 59.247 moles
Mass = Moles × Molar mass
= 59.247 × 34.2 g/mol
= 20,280.25 or
= 20.28 Kg
FeCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of FeCl2 that dissolves.
FeCl2(s) --> Fe+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.76 mol FeCl2/1L × 2 mol Cl⁻ / 1 mol FeCl2 = 1.5 M
The answer to this question is [Cl⁻] = 1.5 M
Answer:
7.7×10^-6
Explanation:
CoCO3(s)<--------> Co^2+(aq) + CO3^2-(aq) Ksp= 1.0 ×10 ^-10
Co^2+(aq) + 6NH3(aq) <-----------> [Co(NH3)6]^2+. Kf = 7.7×10^4
Overall:
CoCO3(s) + 6NH3(aq) <--------> [Co(NH3)6]^2+(aq) + CO3^2-(aq) Knet= Ksp× Kf
Knet= Ksp× Kf = 1.0 ×10 ^-10 ×7.7×10^4= 7.7×10^-6
The insoluble CoCO3 dissolves in the presence of ammonia because bof the formation of hexamine cobalt II complex ion.