All categories

2 years ago

Write the molecular formula of potassium chloride

Chemistry

2 answers:

adell [148]2 years ago

6 0

Answer:

KCl

this is the answer hope its helps you I tried my best to give you the best answer ;)

Naddik [55]2 years ago

4 0

Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

You might be interested in

Is carbon dioxide a pure substance

iVinArrow [24]

Answer:

It is not a pure substance.

6 0

3 years ago

If you have 120. mL of a 0.100 M TES buffer at pH 7.55 and you add 3.00 mL of 1.00 M HCl, what will be the new pH? (The pKa of T

Simora [160]

Answer:

The new pH after adding HCl is 7.07

Explanation:

The formula for calculating pH of a buffer is

pH = pKa + log([Conjugate base]/[Acid])

Before adding HCl,

7.55 = 7.55 + log([Conjugate base]/[Acid])

⇔ log([Conjugate base]/[Acid]) = 0

⇔ [Conjugate base] = [Acid] = 1/2 x 0.100 = 0.05 M

⇒ Mole of Conjugate base = Mole of Acid = 0.05 M x 0.12 mL = 0.006 mol

After adding HCl (3.00 mL, 1.00 M)

⇒ Mole of HCl = 0.003 x 1 = 0.003 mol)

New volume solution is 120 m L+ 3 mL = 123 mL

HCl is a strong acid, it will convert the conjugate base to acid form, or we can express

Mole of new Conjugate base = 0.006 - 0.003 = 0.003 mol

⇒ Concentration = 0.003/0.123 M

Mole of new Acid form = 0.006 + 0.003 = 0.009 mol

⇒ Concentration = 0.009/0.123 M

Use the formula

pH = pKa + log([Conjugate base]/[Acid])

= 7.55 + log(0.003 / 0.009) = 7.07

8 0

3 years ago

Hardness in groundwater is due to the presence of metal ions, primarily Mg2 and Ca2 . Hardness is generally reported as ppm CaCO

Maslowich

Answer:

0.0144 M

1440 ppm

Explanation:

Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In

We use the volume of EDTA consumed in the titration to calculate the moles of Ca⁺² ions:

0.012 L * 0.0600 M * $\frac{1molCa^{+2}}{1molEDTA}$ = 7.20x10⁻⁴ mol Ca⁺²

Now we calculate the molarity:

7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M

To calculate in ppm, we use the moles of Ca⁺² and convert to mg of CaCO₃:

7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃

7.20x10⁻⁴ mol CaCO₃ * 100g/mol * $\frac{1000mg}{1g}$ = 72 mg CaCO₃

Finally, the concentration in ppm is:

72 mg CaCO₃ / 0.050L = 1440 ppm

5 0

2 years ago

How can so many different substances in the world be made of so few elements?

Mrrafil [7]

Matematically speaking, maybe because:
The number of substances = number of elements + number of different combinations of those elements

7 0

3 years ago

Can you help me with this?

Nikitich [7]

Answer:

hi I'm sorry I can't I just need points

6 0

2 years ago

Write the molecular formula of potassium chloride​

Write the molecular formula of potassium chloride