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DaniilM [7]
2 years ago
5

Write the molecular formula of potassium chloride​

Chemistry
2 answers:
adell [148]2 years ago
6 0

Answer:

KCl

this is the answer hope its helps you I tried my best to give you the best answer ;)

Naddik [55]2 years ago
4 0

Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

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Potassium carbonate dissolves as follows:
lara [203]

The 0.25 volume in liters of 1.0 M K_{2}CO_{3} solution is required to provide 0.5 moles of K(aq).

Calculation,

The Potassium carbonate dissolves as follows:

K_{2}CO_{3}(s) → 2K(aq) +CO_{3}^{-2} (aq)

The mole ratio is 1: 2

It means, the 1 mole K_{2}CO_{3} required to form 2 mole of K(aq).

To provide 0.5 mole of K(aq) = 1 mole ×0.5 mole /2 mole required by K_{2}CO_{3}.

To provide 0.5 mole of K(aq) ,0.25 mole required by K_{2}CO_{3}.

The morality of  K_{2}CO_{3} = 1 M = number of moles / volume in lit

The morality of  K_{2}CO_{3} =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

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5 0
2 years ago
Whats the answer? please help me​
dybincka [34]
Answer C
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Explanation
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3 years ago
Why does an aerial require two explosions of black powder
GuDViN [60]

Answer:

to launch aerials and also causes the explosions necessary for special effects like noise or colored light.

Explanation:

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1 year ago
In what areas of the periodic table do you find the most highly reactive elements?
Minchanka [31]

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The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive.

5 0
3 years ago
Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

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7 0
10 months ago
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