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Gemiola [76]
3 years ago
7

what problems might it cause if a company tried to recycle materials without sorting them first? at least 2 or 3 sentences pleas

e!!!!
Physics
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Answer:

They would probably not be looking good.. like if u don't sort it out they won't be shaped well and there are many types of plastic and if we combine them together they won't give the correct form..

hope this helps :)

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Kinetic friction is the frictional force needed to start an object at rest into
Ket [755]

Answer:

b.false i think

Explanation:

i hope i am correct and helps you

7 0
3 years ago
The momentum of an object is 2.5 kg•m/s, and it is travelling at a speed of 100 m/s.
goblinko [34]

Answer:

Refer to the attachment!~

6 0
3 years ago
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

Therefore, the average velocity is 180 km/hr

3 0
3 years ago
Timothy plays basketball in his driveway during the summer. By accident, he left the basketball outside during the winter. He tr
monitta

winter temperature is lower so air molecules move slower n the pressure is lower. ans is A) slower, low

7 0
4 years ago
Read 2 more answers
Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 Å. The atom is placed in a (a) simple cubic
Nuetrik [128]

Answer:

(a) A = 3.90 \AA

(b) A = 4.50 \AA

(c) A = 5.51 \AA

(d) A = 9.02 \AA

Solution:

As per the question:

Radius of atom, r = 1.95 \AA = 1.95\times 10^{- 10} m

Now,

(a) For a simple cubic lattice, lattice constant A:

A = 2r

A = 2\times 1.95 = 3.90 \AA

(b) For body centered cubic lattice:

A = \frac{4}{\sqrt{3}}r

A = \frac{4}{\sqrt{3}}\times 1.95 = 4.50 \AA

(c) For face centered cubic lattice:

A = 2{\sqrt{2}}r

A = 2{\sqrt{2}}\times 1.95 = 5.51 \AA

(d) For diamond lattice:

A = 2\times \frac{4}{\sqrt{3}}r

A = 2\times \frac{4}{\sqrt{3}}\times 1.95 = 9.02 \AA

6 0
3 years ago
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