Answer:
- 3.72 Ns.
9.44 m/s
Explanation:
mass of racket, M = 1000 g = 1 kg
mass of ball, m = 60 g = 0.06 kg
initial velocity of racket, U = 11 m/s
initial velocity of ball, u = 18 m/s
final velocity of ball, v = - 44 m/s
Let the final velocity of the racket is V.
(a) Momentum is defined as the product of mass and velocity of the ball.
initial momentum of the ball = m x u = 0.06 x 18 = 1.08 Ns
Final momentum of the ball = m x v = 0.06 x (- 44) = - 2.64 Ns
Change in momentum of the ball = final momentum - initial momentum
= - 2.64 - 1.08 = - 3.72 Ns
Thus, the change in momentum of the ball is - 3.72 Ns.
(b) By use of conservation of momentum
initial momentum of racket and ball = final momentum of racket and ball
1 x 11 + 0.06 x 18 = 1 x V - 0.06 x 44
12.08 = V - 2.64
V = 9.44 m/s
Thus, the final velocity of the racket afetr the impact is 9.44 m/s .
