Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. The most common use of </span>gravitational potential energy<span> is for an object near the surface of the Earth where the </span>gravitational<span> acceleration can be assumed to be constant at about 9.8 m/s</span>2<span>.</span>
Potential energy due to gravity = Ep = mgh [symbols have their usual meaning ]
Evidently, HALVING the mass will make Ep , HALF its previous value. So, It will be halved.
Answer:
a. 0.947 m/s^2
b. 1304.54 N
c. 0.0966
Explanation:
mass of car = 13500 N = 13500/9.8 = 1377.55 kg
velocity = 50 km/h = 50,000 m/h = 13.9 m/s
raidus = 204 m
a. centripetal acceleartion = v^2/r = 13.9^2/204 = 0.947 m/s^2
b. centripetal force = m*centripetal acceleration = 1377.55 * 0.947 = 1304.54 N
c. In order for the car to round the curve safely, static friction = centripetal force
static friction = coefficient of friction (mu) * mg = mu* 1377.55*9.8 = 13500mu
13500mu = 1304.54
mu = 1304.54/13500 = 0.0966
No because it is dense and opaque
Answer:
The final speed of the train and Bambi after collision is 7.44 m/s
Explanation:
Given;
mass of the train, m₁ = 1000kg
mass of Bambi, m₂ = 75kg
initial speed of the train, u₁ = 8 m/s
initial speed of Bambi, u₂ = 0 m/s
If Bambi gets stuck to the front of the train, then the collision is inelastic.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the final speed of the train and Bambi after collision
Substitute the given values and solve for v
1000 x 8 + 75 x 0 = v (1000 + 75)
8000 = v (1075)
v = 8000/1075
v = 7.44 m/s
Therefore, the final speed of the train and Bambi after collision is 7.44 m/s
