Answer:
R = 2481 Ω
L= 1.67 H
Explanation:
(a) We have an inductor L which has an internal resistance of R. The inductor is connected to a battery with an emf of E = 12.0 V. So this circuit is equivalent to a simple RL circuit. It is given that the current is 4.86 mA at 0.725 ms after the connection is completed and is 6.45 mA after a long time. First we need to find the resistance of the inductor. The current flowing in an RL circuit is given by
i = E/R(1 -e^(-R/L)*t) (1)
at t --> ∞ the current is the maximum, that is,
i_max = E/R
solve for R and substitute to get,
R= E/i_max
R = 2481 Ω
(b) To find the inductance we will use i(t = 0.940 ms) = 4.86 mA, solve (1) for L as,
Rt/L = - In (1 - i/i_max
)
Or,
L = - Rt/In (1 - i/i_max
)
substitute with the givens to get,
L = -(2481 Si) (9.40 x 10-4 s)/ In (1 - 4.86/6.45
)
L= 1.67 H
<u><em>note :</em></u>
<u><em>error maybe in calculation but method is correct</em></u>
Answer:
Explanation:
The energy stored in a spring
= 1/2 k x²
where k is spring constant and x is extension in the spring.
= .5 x 500 x .05²
= .625 J
Work done by friction = energy dissipated
= - μmg x d , μ is coefficient of friction , m is mass , d is displacement
= - .35 x 2.8 x 9.8 x .05
= - .48 J
energy of the mass when it reaches equilibrium position
= .625 - .48
= .145 J
If v be its velocity at that time
1/2 m v ² = .145
.5 x 2.8 x v² = .145
v² = .10357
v = .32 m /s
32 cm /s
Answer: 7 - Transpiration, 6 - Infiltration, 5 - Runoff, 4 - Evaporation, 3 - Precipitation, 2 - Condensation, 1 - Sublimation,
Explanation:
Answer:
TECHNICIAN B
Explanation: Drive shaft is an elongated part of the drive system made of steel of a vehicle that transmits the <em>ENGINE TORQUE to the WHEELS</em> of a vehicle. For proper inspection a technician is expected to completely remove the driveshaft to check all its compactment. It is Cylindrical and usually used for <em>REAR-WHEEL-VEHICLES</em>. Drive shafts are known by different names like propeller shaft,Cardan shaft etc it has different types which range from
<em>One-piece drive shaft
,Two-piece drive shaft to Slip-in-tube drive shaft
.</em>
Answer:
a) 1.25e15 kg
b) 4.17e20 J
c) 44.55 years
Explanation:
To find the volume you need to multiply 218 km * 25 km * 250 m (be careful with units), so the volume is 1.3625e12 m^3, if you multiply this value by the density you will obtain the mass, that is 1.25e15 kg.
To find the energy needed to melt the ice, you use the latent heat, in this case, it is 3.34e5 J/kg. Now you multiply this value by the mass, so you need 4.17e20 J to melt the iceberg.
The surface area of the iceberg is 545e7 m^2, so the ice absorbs 594e9 W, one W is one J/s, so in 12 hours the iceberg absorbs 2.56e16 J, so in 365 days absorbs 9.36e18 J. Now you just divide 4.17e20 J by the amount f energy per year, and obtain 44.55 years.
