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OLga [1]
3 years ago
7

Which graph is a function of x?

Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

a graph of polynomials

hope it helped u

Step-by-step explanation:

Rudiy273 years ago
4 0

Aye bro, need the picture to help.

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Write an equation for the line that is parallel to y=-4x+2 and goes through (0,7)
Soloha48 [4]

Answer:

The answer is

<h2>y = - 4x + 7</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = - 4x + 2

Comparing with the general equation above

Slope / m = - 4

Since the lines are parallel their slope are also the same

Slope of parallel line = - 4

So the equation of the line using point (0,7) and slope - 4 is

y - 7 =  - 4(x - 0) \\ y - 7 =  - 4x

We have the final answer as

<h3>y = - 4x + 7</h3>

Hope this helps you

3 0
3 years ago
Read 2 more answers
Heelp. I will give brainliest to whoever answers correctly.-
Rudik [331]

Answer:

Deliah: 1701/9=189

Dakoda: 1479/9=164.33

Coach should choose Deliah.

Step-by-step explanation:

mean= all the numbers added up/ how many numbers there are

5 0
3 years ago
Solve for x and then find the measure of angle A <br> Angle A=
Mazyrski [523]
<A = <B
5x - 18 = 3x + 42
2x = 60
x = 30

<A = 5(30) - 18 = 132
7 0
3 years ago
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PLS HELP I WILL REALLY APPRECIATE
Serggg [28]

Answer:

$2547 per month

Step-by-step explanation:

849 * 3 = 2547

8 0
3 years ago
Read 2 more answers
Which ordered pairs make the equation true?
Angelina_Jolie [31]

Answer:

(-3, 1) and (2, -1)

Step-by-step explanation:

We'll just substitute in these coordinates.

<u>First Pair:</u>

2(-3) + 5(1) = -1

-6 + 5 = -1

-1 = -1

This works!

<u>Second Pair:</u>

2(5) + 5(-3) = -1

10 - 15 = -1

-5 ≠ -1

This does not work.

<u>Third Pair:</u>

2(2) + 5(-1) = -1

4 - 5  = -1

-1 = -1

This also works!

<u>Fourth Pair:</u>

2(-4) + 5(2) = -1

-8 + 10 = -1

2 ≠ -1

This does not work.

6 0
4 years ago
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